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\(\vec{a}, \vec{b}, \vec{c}, \vec{d}\) be non-zero vectors such that \(\vec{a} \times \vec{b} = \vec{c} \times \vec{d}\) and \(\vec{a} \times \vec{c} = \vec{b} \times \vec{d}\).Then

  • A.\(\vec{a} - \vec{d}\) is parallel to \(\vec{b} - \vec{c}\)
  • B.\(\vec{a} - \vec{b}\) is parallel to \(\vec{b} - \vec{c}\)
  • C.\(\vec{b} - \vec{c}\) is parallel to \(\vec{b} + \vec{c}\)
  • D.\(\vec{a} - \vec{c}\) is parallel to \(\vec{b} - \vec{c}\)
  • E.\(\vec{a} + \vec{c}\) is parallel to \(\vec{b} + \vec{d}\)

Answer: A

The conclusion is \(\vec{a} - \vec{d}\) is parallel to \(\vec{b} - \vec{c}\).

Two non-zero vectors are parallel when their cross product is zero. Expand \((\vec{a} - \vec{d}) \times (\vec{b} - \vec{c})\).

\[ \begin{aligned} &\vec{a} \times \vec{b} - \vec{a} \times \vec{c} - \vec{d} \times \vec{b} + \vec{d} \times \vec{c} \\ &= \vec{a} \times \vec{b} - \vec{a} \times \vec{c} + \vec{b} \times \vec{d} - \vec{c} \times \vec{d} \end{aligned} \]

The given conditions make the first and last terms cancel (\(\vec{a} \times \vec{b} = \vec{c} \times \vec{d}\)) and the middle two cancel (\(\vec{a} \times \vec{c} = \vec{b} \times \vec{d}\)), so the cross product is zero. The other pairings do not reduce to these two conditions.

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