Discussion
The magnitude of \( \mathbf{A} = 3\mathbf{a}_x + 4\mathbf{a}_y \) is
Answer: D
The magnitude is the square root of the sum of the squares of the components, that is \( \sqrt{9 + 16} = 5 \). Dividing the vector by five gives the unit vector \( 0.6\mathbf{a}_x + 0.8\mathbf{a}_y \), whose components are the direction cosines.
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