Machine-translated by Google. Questions are authored in English.
Top

Discussion

The flux of a vector field through a surface is written

  • A.\( \int |\mathbf{A}| \, ds \)
  • B.\( \int (\nabla \cdot \mathbf{A}) \, ds \)
  • C.\( \int \mathbf{A} \cdot d\mathbf{s} \)
  • D.\( \int \mathbf{A} \times d\mathbf{s} \)

Answer: C

Correct answer: \( \int \mathbf{A} \cdot d\mathbf{s} \)

Flux counts only the component of the field passing through the surface, so the dot product with the vector area element is exactly right: it takes the normal component and discards the tangential one. Using the magnitude alone would count field lines running along the surface, which pass through nothing.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.