Discussion
The total number of instantaneous centres for a mechanism containing 'n' links is given by :
Answer: A
The number of instantaneous centres is \(\frac{n(n-1)}{2}\).
Every pair of links in a mechanism has one instantaneous centre. The number of pairs that can be formed from n links is the number of combinations of n taken two at a time.
\[ N = \frac{n(n-1)}{2} \]
A four-bar chain therefore has 6 instantaneous centres. \(n(n-1)\) counts each pair twice, and \((n-1)\) and \((n-1)/2\) undercount.
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