Discussion

The volume of a sphere is 4851 cm³. Its diameter is

Answer: D

Solve for the radius, taking \( \pi = \tfrac{22}{7} \).

\[ \frac{4}{3}\pi r^{3} = 4851 \]

\[ r^{3} = \frac{4851 \times 3 \times 7}{4 \times 22} = \frac{101871}{88} = 1157.625 \]

\[ r = \sqrt[3]{1157.625} = 10.5 \text{ cm} \]

\[ d = 2r = 21 \text{ cm} \]

The question asks for the diameter, so the radius of 10.5 cm must be doubled - stopping at the radius is the intended slip.

No comment is present. Be the first to comment.

Loading…