Discussion

In a swimming pool measuring 90 m × 40 m, 150 men take a dip. If the average displacement of water by a man is 8 m3, then rise in water level is

Answer: D

The men displace their own volume of water, and that volume spreads over the pool's whole surface.

\[ V_{\text{displaced}} = 150 \times 8 = 1200 \text{ m}^{3} \]

\[ \text{pool area} = 90 \times 40 = 3600 \text{ m}^{2} \]

\[ \text{rise} = \frac{1200}{3600} = \frac{1}{3} \text{ m} = 33.33 \text{ cm} \]

The answer is asked for in centimetres, so the metre figure must be multiplied by 100 - the whole point of the awkward-looking 33.33.

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