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Given that 1 cu. cm of marble weighs 25 g, the weight of a marble block of 28 cm in width and 5 cm thick, is 112 kg. The length of the block is

  • A.36 cm
  • B.37.5 cm
  • C.32 cm
  • D.26.5 cm

Answer: C

Convert the weight to a volume using the given density, then divide out the two known dimensions.

\[ 112 \text{ kg} = 112000 \text{ g} \quad\Longrightarrow\quad V = \frac{112000}{25} = 4480 \text{ cm}^{3} \]

\[ V = l \times b \times h \quad\Longrightarrow\quad l = \frac{4480}{28 \times 5} = \frac{4480}{140} = 32 \text{ cm} \]

The kilogram-to-gram conversion is essential: the density is quoted per cubic centimetre in grams, so the weight must be in grams too.

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