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50 mL of a water sample required 12 mL of EDTA, 1 mL of which is equivalent to 1 mg of CaCO\( _3 \). The total hardness is

  • A.24 ppm
  • B.600 ppm
  • C.240 ppm
  • D.12 ppm

Answer: C

Twelve millilitres of EDTA correspond to twelve milligrams of calcium carbonate equivalent in the 50 millilitre aliquot, which is 240 milligrams in a litre. Scaling the titration volume up to a litre is the step most often got wrong in this calculation.

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