Discussion
An undercarriage weighing \( 3.6 \) t on the same \( 90 \) t aircraft represents
Answer: A
Correct answer: 4 per cent
\[ \frac{3.6}{90} = 0.04 = 4\ \text{per cent.} \] Undercarriage groups typically fall between three and five per cent of take-off weight, so this is a normal figure. It is worth remembering against the distractor that offers a fifth of take-off weight - no aircraft carries an undercarriage anything like that heavy.
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