Discussion
Burning \( 2 \) t from a tank \( 3 \) m aft of the centre of gravity on a \( 80 \) t aircraft moves the centre of gravity forward by
Answer: D
Correct answer: 0.077 m
Burning fuel removes weight, so both the total and the moment change: \[ \Delta x = \frac{w \times d}{W - w} = \frac{2 \times 3}{80 - 2} = \frac{6}{78} = 0.077\ \text{m forward.} \] The denominator is the weight remaining, not the weight before - using 80 gives 0.075 m, close enough here to look plausible, which is why the distinction is worth being deliberate about.
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