Discussion
A tunnel with a turbulence factor of \( 1.4 \) is run at a Reynolds number of \( 200\,000 \). The effective free-air Reynolds number is
Answer: D
Multiplying, \( 1.4 \times 200\,000 = 280\,000 \). The tunnel's own turbulence promotes transition, so the model behaves as it would at a higher Reynolds number in still air. Dividing rather than multiplying is the usual error and gives 143,000.
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