Discussion
A model reads a drag of \( 30 \) N, of which the buoyancy correction accounts for \( 1.5 \) N. The corrected drag is
Answer: C
Horizontal buoyancy is a spurious rearward force produced by the tunnel's own streamwise pressure gradient, so it is subtracted: \( 30 - 1.5 = 28.5 \) N. Five per cent is a significant share of a drag measurement, which is why many tunnels use slightly diverging walls to remove the gradient at source.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development