Discussion
A and B can do a work in 10 days. They start the work together but A leaves after 2 days and B completes the rest of the work in 12 days. In how many days can A do the work alone?
Answer: D
Work done by A and B in 2 days = 2/10 = 1/5. Remaining work = 4/5. B completes 4/5 of the work in 12 days. So B can complete the full work in \(12 \times 5/4 = 15\) days. B's one day work is 1/15. (A+B)'s one day work is 1/10. A's one day work = \(1/10 - 1/15 = (3-2)/30 = 1/30\). A alone takes 30 days.
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