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Find the Z-transform of following function:

\(x(n) = a^n u(n) + b^n u(-n - 1)\)

  • A.\(X(Z) = \dfrac{1}{Z - a} - \dfrac{1}{Z - b}\)
  • B.\(X(Z) = \dfrac{Z}{Z - a} + \dfrac{Z}{Z - b}\)
  • C.\(X(Z) = \dfrac{1}{Z - a} + \dfrac{1}{Z - b}\)
  • D.\(X(Z) = \dfrac{Z}{Z - a} - \dfrac{Z}{Z - b}\)

Answer: D

The first term is a right sided sequence and the second is a left sided one, and each has a standard transform.


\[ a^n u(n) \leftrightarrow \frac{z}{z - a},\ |z| \gt |a| \]


\[ b^n u(-n-1) \leftrightarrow -\frac{z}{z - b},\ |z| \lt |b| \]


Adding them gives


\[ X(z) = \frac{z}{z - a} - \frac{z}{z - b} \]


The minus sign comes from the left sided term, so the options with a plus are wrong, and the options without \(z\) in the numerator are the transforms of delayed sequences. The answer is option D.

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