Discussion
Match the Thermodynamic laws in Column I with the description given in Column II
| Column I | Column II | ||
|---|---|---|---|
| P | Zeroth law | 1 | Entropy of a perfect crystal at 0 K is zero |
| Q | First law | 2 | Introduces Entropy |
| R | Second law | 3 | Defines thermal equilibrium |
| S | Third law | 4 | Defines internal energy |
Answer: A
The correct matching is P → 3; Q → 4; R → 2; S → 1.
- Zeroth law: two systems each in thermal equilibrium with a third are in equilibrium with each other, which defines thermal equilibrium and temperature (3).
- First law: energy conservation, \(\Delta U = Q - W\), which introduces internal energy as a property (4).
- Second law: introduces entropy and the direction of spontaneous processes (2).
- Third law: the entropy of a perfect crystal at 0 K is zero (1).
Every other option assigns entropy at 0 K or thermal equilibrium to the wrong law.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development