Your Answer : (Not Answered)

Correct Answer : A

The answer is about 13 per cent. For 2012 add the candidates selected in the five districts: 82 + 70 + 48 + 65 + 55 = 320. Add those who qualified: 640 + 560 + 400 + 525 + 350 = 2475. The required percentage is \[\frac{320}{2475} \times 100 \approx 12.9\] which is about 13 per cent. The options 10, 8 and 15 per cent are further from 12.9. The table was read from the page image, where the 2014 Bankura appeared figure reads 4500.

Your Answer : (Not Answered)

Correct Answer : B

The value of B is 4.

The units digit of A × 6 must be 8, so A is 3 or 8. A = 3 gives 18, and then 6B + 1 must end in 8, which is impossible. A = 8 gives 48 with a carry of 4, so 6B + 4 must end in 8, which needs 6B to end in 4, so B = 4 (24 + 4 = 28, carry 2, C = 2).

\[ 48\times6=288 \]

2, 6 and 1 do not give a product of the form C88.

You can check the result by multiplying: 48 × 6 = 288, which has the form C88 with C = 2. A trial with A = 3 gives 43 × 6 = 258 and 63 × 6 = 378, which end in 8 but do not have 8 in the tens place. So only A = 8 with B = 4 works.

Your Answer : (Not Answered)

Correct Answer : B

There are 119 girls behind her.

With 150 students in the ratio 1 : 5, there are 25 boys and 125 girls. Saranya has 5 girls in front of her, and she herself is a girl:

\[ 125 - 5 - 1 = 119 \]

Her overall position (22nd) is not needed, since only girls are counted. 145 counts every student except the 5 girls in front, and 150 is the whole class; 109 does not follow from the counts.

Your Answer : (Not Answered)

Correct Answer : B

The top view is Q.

The hill rises steeply on the side near 0 km and falls gently on the far side, with its summit at about 0.22 km. The cross-sections higher up the hill are smaller ovals, and they are centred close to the summit, near the 0 km end. Seen from above, the nested ovals therefore crowd together close to the 0 km mark, where the slope is steep, and spread out on the far side, where the slope is gentle.

Q shows exactly this: the smallest ovals sit near the left, close to 0 km. P puts the summit at the far end, as if the gentle slope faced 0 km. R has evenly spaced, concentric ovals, which would describe a symmetric hill. S does not shift the ovals steadily in one direction.

Your Answer : (Not Answered)

Correct Answer : D

Correct answer: SQPR

The sentence reads:

Every body in the universe, whether big or small, attracts every other body with the force of gravitation.

S and Q both describe every body, so they stay with the subject, and only then can the verb in P arrive. R completes every other with its noun and adds the instrument.

Your Answer : (Not Answered)

Correct Answer : B

It is parturition.

Parturition is the act of giving birth, from the Latin parere, to bring forth. Delivery is the everyday word, and conception is the beginning rather than the end of the process.

Your Answer : (Not Answered)

Correct Answer : A

The opposite is pacific.

Pugnacious means eager to fight, from the Latin pugnus, a fist. Pacific means peace-making, from pax.

Your Answer : (Not Answered)

Correct Answer : D

Correct answer: none of the mentioned

Ethernet, DSL and FDDI all define how stations share the medium, so each includes a media access control method. None of them is the exception.

Your Answer : (Not Answered)

Correct Answer : A

Correct answer: True

Generalisation runs upward: several specific entity types are examined, their common attributes and relationships are abstracted, and a supertype is created to hold them. Specialisation runs the other way, from one general type down to subtypes - the two processes arriving at the same structure from opposite directions.

Your Answer : (Not Answered)

Correct Answer : B

Correct answer: False

If the parent is required, a child row may only be inserted when a parent already exists for it to refer to, so the insertion has to be checked or the parent created first. The action that is always permitted in that case is inserting a new parent, since a parent needs no child.

Your Answer : (Not Answered)

Correct Answer : B

Adding a parameter creates an overload, not an override, so Thread's own no-argument run() is what start() invokes. That inherited method has no Runnable to delegate to and does nothing, so the counter is never incremented and only main's line appears. @Override on the method would have turned the mistake into a compile error.

Your Answer : (Not Answered)

Correct Answer : C

Correct answer: Both Statement I and Statement II are correct

Both are true and the second explains the first. The rate of absorption depends on the difference between the actual and equilibrium concentrations at the interface. In physical absorption the dissolved gas accumulates and that difference shrinks; in chemical absorption a reagent consumes it as fast as it dissolves, holding the free concentration near zero and the driving force near its maximum. This is why sulphur dioxide is scrubbed with an alkaline slurry rather than with water.

Your Answer : (Not Answered)

Correct Answer : B

The critic observes the percepts and reports performance against a fixed external standard, since the agent's own utility function cannot be used to judge whether that utility function is right. Without an external standard the agent could improve its score by changing its opinion of what counts. Architecture, algorithm selection and exploration belong elsewhere. Requiring the feedback to come from outside the system being improved is what makes the learning meaningful.

Your Answer : (Not Answered)

Correct Answer : A

An active radar resolves the precipitation in the vertical, revealing the bright band, the depth of the rain layer and the structure of convective cores. Passive radiometers integrate through the whole column and cannot separate the levels. Dual frequency radar does constrain the drop size distribution statistically, though not drop by drop.

Your Answer : (Not Answered)

Correct Answer : D

Each separated term is a function of one coordinate, so matching a condition term by term requires the boundary to be a surface of constant coordinate. An oblique boundary defeats the method and a numerical or conformal approach is used instead.

Your Answer : (Not Answered)

Correct Answer : D

The statement that is not true is that development occurs via equal simultaneous growth of social overhead capital and directly productive activity.

Hirschman's theory is about imbalance. Development can proceed either through excess capacity of social overhead capital (SOC), where infrastructure built first invites directly productive activities (DPA), or through shortage of SOC, where DPA grows first and the resulting bottlenecks push the state to build infrastructure. He applied this especially to underdeveloped countries.

Equal, simultaneous growth of SOC and DPA is balanced growth, which is the opposite of Hirschman's position.

Your Answer : (Not Answered)

Correct Answer : B

The correct matching is p-2, q-4, r-1, s-3. Depression is explained by a negative attribution style, schizophrenia by the dopamine hypothesis, phobia by classical conditioning, and Korsakoff's syndrome is linked to alcoholism through thiamine deficiency.

The other codes link depression with alcoholism or phobia with the dopamine hypothesis, which does not fit the explanations.

Your Answer : (Not Answered)

Correct Answer : A

The body is NCERT, the National Council of Educational Research and Training.

NCERT is the national body for research, publication and resource work in school education, and compiling reference material such as a dictionary or encyclopaedia of Indian education fits that publication and research role.

SCERT is the state-level counterpart and works within one state, UGC funds and coordinates universities and higher education, and NCTE regulates teacher-education institutions and their norms. None of these three has reference publishing as a defining function.

I could not find a source that lists a dictionary or encyclopaedia among NCERT's formal functions, so this rests on elimination and on the University's key.

Your Answer : (Not Answered)

Correct Answer : B

The reaction becomes diffusion controlled when k_r \(\gg\) k_esc.

If the encounter pair reacts much faster than it can separate, almost every encounter leads to product, and the denominator reduces to k_r:

\[ \begin{aligned} \frac{d[\text{P}]}{dt} &= \frac{k_{r}k_{enc}}{k_{esc}+k_{r}}[\text{A}][\text{B}] \\ &\approx k_{enc}[\text{A}][\text{B}] \end{aligned} \]

The rate then depends only on how fast the reactants meet, which is set by diffusion through the solvent. In the opposite limit, k_r \(\ll\) k_esc (option A), the rate becomes (k_rk_enc/k_esc)[A][B]: the reaction is activation controlled. Options C and D do not reduce the expression to the encounter rate.

Your Answer : (Not Answered)

Correct Answer : C

The posterior mean is 5/4.

The prior \(q\lambda e^{-3\lambda}\) is a Gamma density with shape 2 and rate 3. With one Poisson observation x = 3 the likelihood is proportional to \(\lambda^{3}e^{-\lambda}\), so

\[ \begin{aligned} \pi(\lambda \mid x) &\propto \lambda^{3}e^{-\lambda} \cdot \lambda e^{-3\lambda} \\ &= \lambda^{4}e^{-4\lambda} \end{aligned} \]

which is Gamma with shape 5 and rate 4. Its mean is \(5/4\).

4/5 inverts the shape and rate, and 3/5 and 2/5 use the wrong shape or rate.