APSC Assistant Engineer 2024: Assistant Engineer, Public Health Engineering Department (Advt. 28/2023), Electrical Engineering

Text of page 1
AElPIJ3lEEltu24
DO NOT OPEN THIS TEST BOOKLET UNTIL YOU ARE ASKED TO DO
SO
Test Booklet No. : Series
TEST BOOKLET
00565 Paper-II
( tLEcrRrcAL ENcINEERTNG )
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Text of page 2
1. Floating battery systems are widely 4, The Thevenin equivalent of a circuit
used for operating at ro= 5 rad/s has
(A) power station Voc = 3'72-15'9V
Zo =2'a+ jO'67 o
(B) emergency lighting
At this frequency, the minimal
(C) telephone exchange installa- realization of the Thevenin
tion impedance will have
(D) All of the above (A) a resistor, a capacitor and an
inductor
(B) a resistor and a capacitor
2. The Thevenin voltage and resistance
(C) a resistor and an inductor
of the given circuit seen from
terminalsaandbare (D) a capacitor and an inductor
U. A complex current wave is given by
i = 5 + Ssin 1o0rt A, The average
value will be
(A) l0 A (B) 0A
(A) 2Vand 1C) (c) Jso- e (D) sA
(B) 4Vand 1C) 6. A resistance of 5 Q is connected in a
branch of a network. The curent
(c) lv and 1o in this branch is 2 A. If this S A
2
resistor is replaced by a 1O Sl
(D) lVand2Q resistor, the cunent in the branch
(A) may be more or less than 2 A
3. In the given circuit, the value of V is (B) will be more than 2 A
equal to (C) will be less than 2 A
2A (D) will be 2 A
7. TWo incandescent lightbulbs of 4O W
and 60 W rating are coffrected in
series acros! the mains. Then
(A) 10 v (A) the bulbs together con$ume
100 w
(B) 0v (B) the bulbs together consume
(c) 14 v 50w
(C) the 60 W bulb glows brighter
(D) 12 v (D) the 40 W bulb glows brighter
AE/PHE IEE/il 124136-a 2
Text of page 3
A practical current source is usually 11. A circuit with resistor, inductor and
represented by capacitor in series is resonant at
fs Hz , lf all the component values
(A) a resistance in series with an are now halved, the new resonant
idea-l current source . frequency is
(B) a resistance in parallel with an (Al 2fs Hz
ideal current source
(B) still f6 Hz
(C) a resistance in parallel with an
ideal voltage source (cl (fs lal Hz
(D) None of the above (Dl (f s /21 Hz
9. A dead storage battery can be revived In the given circuit, ammeter A2
by reads 4 A and ,{3 reads 3 A' Then Al
will read
(A) a dose of H2SOa
(B) adding so-called battery
restorer
(C) adding distilled water
(D) None of the above
(A) 7A
10. In the given circuit, the initial (B) lA
capacitor voltage i3 zero. The switch
is closed at t = 0. The final steady- (c) 4A
state voltage across the capacitor is
(D) sA
13, Given two coupled inductors 11 and
100 v 10 c) L2; their mutual inductance M
satisfres
$ M=ff4
(A) 100 v
@l r,r >\)!z
(B) s0 v
(c) 2s v lcl M > .,lL1L2
(D) 0v tDt M<Jt6,'
AEIPIJE.IE,EII] 124136-a 3 I P.r.o.
Text of page 4
14. The electric field strength between 12. which of the following statements
. two charges -5Q and +2Q separated holds true for divergence of electric
by 50 cm is zero and magnetic flux densities?
(A) at midway between them (A) Both are
"Ero.
(B) They are zero for static
(B) at perpendicular bisector densities but non-zero for
time-varying densities.
(c) beyond the pooitive charge (c) It is z.ero lor the electric flux
densigr.
(D) beyond the negative charge
" (D) It is z.eto for the magnetic flux
density.
15. Identiff the Maxwell's equation from lg. In a uniform electric lield, the field
the following. fines at equipotential surfaces
(A) v.d=p, (A) are parallel to one another
(B) intersect at 45.
(B) vxB=o (C) intersect at 30o
(D) are orthogonal
(c) f'.a7=o
19. If B is the electric field intensity,
(D) All of the above then V . p x B) is equal to
(A) d
16. A single-phase diode bridge rectilier 18) lBl
. supplies a highly inductive load.
The load current can be assumed to (C) null vector
be ripple free. The a.c. supply side
current waveform will be (D) zero
(A}sinusoidal2o.Adynamometer-wpewattmeter
ponds to the
(B) constant d.c. (A) average value of active power
(B) average value of reactive power
(C) square
(C) peak value of active power
(D) triangular (D) peak value of reactive power
AEIPflE/EE/fi/24136-A 4
Text of page 5
21. The two-watuneter method is used to 24. A moving-coil instrument gives a
measure active Power on a 3-Phase, full-scale deflection with a current
3-wire system, If the phase voltage
'
of 40 pA, while the intemal
is unbalanced, then the Power resistance of the meter is 500 A. It
reading is is to be used as a voltmeter to
(A) affected bY both negative measure a voltage range of G-10 V.
sequence and zero sequence The multiplier resistance needed is
voltages equal to
(B) aflected by negative sequence (4 2498.s krl
voltage but not bY ?.ero
sequence voltage (B) 24OO ko
(C) afected bY zero sequence
voltage but not bY negative
(c) soo ko
sequence voltage (D) 1o0o ko
(D) not a{Iected by negative or zero
sequence voltage
25. The current passing through a 1O O
resistor is given by
22. A pressure gauge is calibrated from
G-50 kN/m2. It has a uniform scale i = 3 + 4.Esin3l4t A
with 10O scale divisions' One-fifth
of the scale divisions can be read This current is measured bY a
with certainty. The gauge has PMMC meter. The measured value
is
(A) resolution of O'1 kN/m2
(B) threshold of O'1 kN/m2 (A) 3A
(C) dead zone of 0'2 kN/m2
(B) sA
(D) resolution of O'5 kN/m2
(c) 4A
23. A Wheatstone bridge is balanced
with all the four resistances equal (D) 4.8 A
to I kO each, The bridge suPPlY
voltage is 1OO V, The value of one
26. In 2's complement representation,
of the resistances is changed to the number l1fOOlOl rePreaents
1O1O O. The outPut voltage is
the decimal number
measured with a voltage-measuring
device of inlinite resistance. The (A) + 31
bridge sensitivity is
(A) 10 v/a (B) - 31
(B) 2's mv/Q (cl +27
(c) 25 mv/o
(D) None of the above lDl -27
AEIPHE/E,Elrr/2413,6-a 5 I P.T.o.
Text of page 6
27" For tJ:e minterm designation 31. The bridge method commonly used
r = Em(l, 3, 5, 7), the complete for finding mutual inductance is
expression is
(A) Heaviside-Campbetl bridge
(^l Y =ABj+ABC
(B) Schering bridge
(Bl y =ABC+ABC+AE1+ABC
(C) De Sauty bridge
(cl v =ABe +AEc+ABc+AEC
(D) Wien bridge
(D) y=AEe+ABC+AEj+ABc
32. The typical ratio of holding current to
24. De Morgan's second theorem is latching current in a 20 A thyristor
(A) a.A=o is
(s) 7=a (A) s
(cl TiB=V.B lBl 2
(D) E=a-+E (c) 1
(D) o.s
29. Two 16: I multiplexers and one
2: I multiplexer can be connected A 3-phase full converter operates at
to form a/an 5O Hz. The ripple frequency in
(A) 16: I multiplexer the output voltage is
(B) 32: l multiplexer (A) so Hz
(B) l0O Hz
lOl 64:1 multiplexer
(D) 8: l multiplexer (c) lso Hz
(D) 300 Hz
30. An SCR is considered to be a
semi-controlled device because 34, Consider the function
(A) it can be turned OFF but not F(s) =
ON with a gate pulse s(s2 +3s+2)
(B) it conducts only during one where F(s) is the Laplace transform
half cycle of an alternating of the function ..;f(t). The initial value
current wave of /(t) is equal to
(C) it can be turned ON but not (A) s
OFF with a gate pulse
lBl s /2
(D) it can be tumed ON only
during one half cycle of an (c) s/3
alternating voltage wave (D) o
AE lPHE/E,E/l/24I36-a
Text of page 7
35. The characteristic equation of a 39. If the loop gain K of a negative
system is given by feedback system having a loop
transfer function
3sa + 10s3 + 5s2 +2 = 0
K(s + 3)
-----------_-=
This system is
(s + 8)'
(A) unstable
(B) marginally stable is to be adjusted to induce a
(C) stable sustained oscillation, then
(D) linear (A) the frequency ofthis oscillation
Signal flow graph is used to obtain must be a rad/s
J3
(A) the stability of a system
(B) the controllability of a system (B) the frequency of this oscillation
(C) both stability and control- must be 4 radls
lability of a system
(C) the frequency of tl:is oscillation
(D) the transfer function of a
system
must be 4 or I 10 radls
37. The principles of homogeneity and
(D) such K does not exist
superposition are applied to
(A) linear time-invariant systems
40. Consider the signal flow graPh
(B) non-linear time-invariant
shown in the given frgure :
sYstems
(C) linear time-variant systems
(D) non-linear time-variant
systems
A boost converter is operated in the
continuous conduction mode in
steady state with a constant duty -1
ratio D. If I/o is the magnitude of the The C(s)/R(s) will be
DC output voltage.and V" is the
GlG2Gs
magnitude of the DC input voltage, (A)
7- GLG2HT + G2G3H2 + G|G2G3
then the ratto Vo fV, is given by
(A) D GlG2Gs
(B)
(B) 1 l+ GtG2Hr + G2G|H2 + G|G2G3
D
1 GrG2G3
(c) (c)
t- D l- G1G2H1- G2G|H2 - G|G2G3
(D)
D
1-D (D) None of the above
AE/PHE lEElrr/24136-A 7 lP.T.O.
Text of page 8
4L. The Laplace transformation of the 43. A bulb in a staircase has two
function svdtches, one switch being on the
A ground floor and the other one at
fltt = for 0<t<to Iirst floor. The bulb can be turned
,ot
ON and also can be turned OFF by
0; for t<o,to<t any one of the switches irrespective
is of the state of the other switch.
The logic of switching of the bulb
resembles
(A) I (1 - e-sto )
(A) an AND gate
(B) e-sro) (B) an OR gate
14(1-
(C) an XOR gate
(C) 4 (1 - e-'roa ) (D) a NAND gate
44. A cascade of three identical
(D) a(1-e{oA} modulo-S counters has an overall
modulus of
(A) s
42. Two in-phase 5O Hz sinusoidal wave-
forms of unit amplitude are fed into (B) 2s
channel-l and channel-2 respec-
tively of an oscilloscope. Assuming
(c) 12s
that the voltage scale, time scale (D) 62s
and other settings are exactly the
same for both the channels,
what would be observed if the 45. Thyristor circuits that directly
oscilloscope is operated in x-g convert polyphase AC voltage from
mode? one frequency to another frequency
are called
(A) A circle of unit radius
(A) regulator
(B) An ellipse
(B) converter
(C) A parabola
(C) bidirectional converter
(D) A straight line inclined at 45.
with respect to the x-axis (D) cycloconverter
AE /PHE /EE /tr 124136-A
Text of page 9
46, In the given transistor circuit, the The nature of feedback in the
collector to ground voltage is +20 V. OPAMP circuit shown below is
Which of the following is the
probable cause of error?
+20 v
10 ko
(A) voltage-voltage feedback
(B) voltage-current feedback
(C) current-current feedback
(A) Collector-emitter terminals
shorted (D) current-voltage feedback
(B) Emitter to ground connection 49. In forward voltage triggering,
open thynistor
(A) changes from OFF state to oN
(c) l0 krl resistor open state
(D) Collector-base terminals (B) inverts the state
shorted
(c) changes from ON state to OFF
state
(D) state remains the same
In a thyristor converter, a free-
47. The complete set of only those logic wheeling diode is used to
gates designated as universal gates
is (A) add to the conduction curent
of the thyristor
(A) NOT and NAND gates
(B) oppose the thyristor conduc-
tion
(B) XNOR, NOR and NAND gates
(c) conduct current during the
OFF period of the thristor
(C) NOT, OR and AND gates
(D) protect the thyristor by
(D) XOR, NOR and NAND gates providing a shunt path
9 I P.T.O.
^ElPHElEElrU24ls6-a
Text of page 10
51. A DC chopper has a resistive load of Which of the following devices can be
1O a and an input voltage of 22O y . considered as a clipping circuit?
When the chopper is ON, its voltage
drop is 2 V and the chopping (A) Full-wave converter
frequency is I kHz. If the duty cycle
is 50%, the average output voltage (B) Half-wave rectifier
will be
(C) Bridge rectifrer lvith a
(A) l0o v smoothing capacitor
(B) 103 v (D) Common-base conliguration of
A BJT
(c) 106 v
t 5. A half-wave rectirier with silicon
(D) 109 v
diode produces (peak) maximum
load current of 50 mA through a
62. A step-up chopper has input voltage 1200 Q resistor. If the voltage drop
of 100 V and output voltage of across the diode is 0'7 V, the PIV of
300 V. If the non-conducting time the diode will be
of thyristor chopper is 100ps, the
pulse width of the output voltage is
(A) 48.7 v
(B) 48 v
(A) 200 ps
(B) 100 ps
(cl 24 v
(D) s0 v
(C) 300 ps
(D) 5O ps In frequency modulation
(A) carrier amplitude is changed
53. A clamping circuit by the modulating signal
(A) adds a Di component to an AC (B) carrier frequency is changed by
signal either side the modulating signal
(B) adds an AC component to a DC (C) if amplitude of modulating
signal either side signal increases, the carrier
frequency remains constant
(C) adds a DC component to an AC
signal in positive direction (D) frequency of the carrier must
be lower than the modulating
(D) None of the above frequency
AEIPHE/DE/l/24136-A 10
Text of page 11
57. In the feedback network of the given 6O, A digital-to-analog converter with a
figure, if the feedback factor k is full-scale outPut voltage of 3 5 V
increased, then has a resolution close to 14 mV.
Its bit size is
(A) 4
(B) 8
(c) 16
(D) 32
61. List-I lists different appliances and
(A) input impedance increases and List-U lists motors for these
output impedance decreases appliances. Match the aPPliance
with the most suitable motor and
(B) both input and output impe- choose the right combination
dances increase
among the choices given :
(C) both input and outPut
impedances decrease List'I Li.st-11
a. Food mixer 1. Permanent
(D) input impedance decreases magnet DC motor
and outPut imPedance b. Cassette tape 2, Single-phase
increases recorder induction motor
Domestic water 3, Universel motor
58. Which of the following is a result pump
of over-modulation? Escalator 4. Three-phase
(A) Weakening of signal induction motor
5, DC series motor
(B) Distortion 6. Stepper motor
(C) Strengthening of signal
Codes :
(D) Excessive carrier Power
59. For ttre equation (A) a b c d
364
i(t)+ 3i(r)+ 2x(t) =s
(B) a b c d
the solution x(t) approaches which 1 J 2 4
of the following values as t + -?
(A) 0 (c) a b C d
3 1 2 4
(Bl s/2
(c) s (D) a b c d
(D) 10 .1 2 I 4
AE1PHElEElrrl24ls6-A 11 I P.r.o.
Text of page 12
62. A 4-pole lap-wound DC generator 65. The core losg and copper loss of a
has a developed power of p watts transformer on full load are 400 W
and a voltage of E volts. Tlrro and 600 W respectively. Their
adjacent brushes of the machine values at one-third of full load
are removed as they are wom out. If will be
the machine operates with the
remaining btushes, the developed
voltage and power that can be (A) 133.3 W and 200 W
obtained from the machine are
(A) 4 votts and I watts (Bl 400 W and 66.66 W
22
(B) E volts and I watts
2 (C) 133.3 W and 600 W
(C) E volts and I watts
4 (D) 4o0 W and 20OW
(D) E volts and P watts
63. A DC machine is connected to 22OV
supply mains. Its armature 66. A 5 kVA, 1O0O/200 V, 50 Hz, singte-
resistance is 0.2 O The magnitude phase transformer has the following
of e,m.f. generated so that it may no-load and short-circuit test data :
feed 100 A to supply is
No-lod.d.
(A) 200 v test : WO = 90 W, IO=L-2A, V=2OOy
Sttott-
(B) 220 v circllit
test : lysc = ll0 W, Isc = 5A ysc = 50V
(c) 240 v
The full-1oad copper loss and iron
(D) 260 v loss will be
64. A 4-pole, 5O Hz, 4O0 V, three-phase
induction motor is running at (A) 90 W and 110 W
1440 r.p.m. The frequency of the
rotor induced e.m.f. is
(B) r10 W and lO0 W
(Al 2 Hz
@l aHz (C) 110 W and 9O W
(Cl l Hz
(D) 50 Hz (D) 90 W and 9O W
A lPHE ln.E/rrl24l3,6-A t2
Text of page 13
67. Coggrng and crawling are pheno- 69. The e.m.f. induced in the armature
mena associated with of a DC generator is altemating in
nature but in the output circuit,
DC is made available by
(A) cage induction machines and
they are essentially the same
(A) brush and slip-ring arrange-
ment
(B) squirrel-cage induction
machines, the former at a (B) brush and commutator
fraction of its rated speed and arrangement
the latter during starting
(C) diode rectifiers
(C) squirrel-cage induction
machineg, the former during
starting and the latter at a
(D) converter circuit
fraction of its rated speed
For synchronizing an alternator with
(D) wound-rotor induction the bus bar, which of the following
machines and they are reduced conditions is not applicable?
by skewing, chording and
distribution of windings
(A) The generated voltage of the
alternator should be equal to
the bus bar voltage
A large capacity 3-phase induction
motor is started using a star-delta (B) The frequency of the generated
starter instead of DOL starter, The voltage should be equal to the
current bus bar frequency
(A) is increased three times (C) The phase sequence of the
voltage generated should be
the same as that of the bus bar
(B) remains constant voltage
(C) is reduced to one-third of its (D) The kVA rating of the
value alternator should be equal to
the kVA rating of the other
alternators already connected
(D) is reduced to half of its value to the bus bar
AE/PHE/EE/rr/24136-a 13 lP.T.O.
Text of page 14
71. Which of the following statements is In a split-phase capacitor-start
not true for a synchronous motor? induction motor, a time phase
difference between the currents
(A) An over-excited synchronous flowing through the two windings of
motor draws lagging power
the stator is produced by
factor.
(A) placing the two windings at an
(B) An over-excited synchronous angle of90" in the stator slots
motor draws leading power
factor. (B) applying two-phase supply
across the two $,indings
(c) At normal excitation, the
current drawn by a synchro- (C) introducing capacitive reac-
nous motor is the minimum. tance in the auxiliary winding
circuit
(D) At normal excitation, the power
factor of the current drawn is (D) connecting the two windings
unity. in series opposition across a
single-phase supply
In a DC machine, which of the
following statements is true? 74. lt is deshable to eliminate
(A) Compensating winding is used
sth harmonic voltage from the
phase voltage of an altemator. The
for neutralizing armature
coils should be short pitched by an
reaction while inter-pole
electrical angle of
winding is used for producing
residual flux. (4 30'
(B) Compensating winding is used (B) 36'
for neutralizing armature
reaction while inter-pole (cl 72.
winding is used for improving
(D) 18'
commutation.
(c) Compensating winding is used A four-point starter is used to start
for improving commutation and control the speed of a
while inter-pole winding is
used for neutral2ing armature (A) DC shunt motor with armature
reaction. resistance control
(D) Compensating winding is used (B) DC shunt motor witJ: field
for improving commutation weakening control
while inter-pole winding is (C) DC series motor
used for producing residual
flux. (D) DC compound motor
AE/PHEIEE/rr 124136-A L4
Text of page 15
The r.m.s. value of a half-wave 79. If the fault current is 2000 A,
rectilied symmetrical square-wave the relay setting is 5O% and CT
voltage of 2V is ,.tio i" 490, then the plug setting
5
(4 JZv multipter will be
(B) 1v (A) 2s
1
(B) ls
(c)
J2
(c) 50
(D) .rB V
(D) 10
77. The rated voltage ofa 3-phase power
8O. The relay that has capability of
system is given as
anticipating the possible major fault
in a transformer is
(A) r.m.s. phase voltage
(A) over-current relay.
(B) peak phase voltage
(B) differential relay
(C) r.m.s. line-to-line voltage
(C) Buchholz relay
(D) peak line-to-line voltage
(D) None of the above
78. Consider a long, two-wire line
composed of solid round con- 81. The per unit impedance of a circuit
ductors. The radius of both the element is O'30. If the base kV and
conductors is O'25 cm and the base MVA are halved, then the
distance between their centres is new value of the Per unit
1 m. If this distance is doubled, impedance of the circuit element
then the inductance per unit length wiU be
(A) doubles (A) 0.30
(B) halves (B) 0'60
(C) increases but does not double (c) o.0030
(D) decreases but does not halve (D) 0.0060
AEIPHE/E,ElII124136-A lP.T.O.
Text of page 16
42. The transient stability of a power 85. To avoid maloperation of differential
system can be effectively improved protection of transformers
by connected in A-Y mode, the CT
must be connected in
(A) excitation improvement
(A) Y-A mode
(B) phase-shifting transformer
(B) Y-Y mode
(C) single-pole switching of circuit (C) A-Y mode
breakers
(D) A-A mode
(D) increasing the turbine valve
oPening For enhancing the power trans-
mission in a long EHV transmission
line, the most prefered method is
A lightning stroke discharges an to connect a
impulse current of l0 kA (peak) on
(A) series inductive compensator
a 400 kV transmission line having
. surge impedance of 250 SI The
in the line
magnitude of transient over-voltage (B) shunt inductive compensator
travelling waves in either direction at the receiving end
assuming equal distribuuon from
the point of lightning strike will be (C) series capacitive compensator
in the line
(A) 12s0 kv (D) shunt capacitive compensator
at the sending end
(B) 16s0 kv
(c) 2so0 kv 47. The angle 6 in the swing equation of
a synchronous generator is the
(D) 2900 kV (A) angle between stator voltage
and current
84, A negative sequence relay is (B) angular displacement of the
commonly used to protect rotor u/ith respect to the stator
(C) angular displacement of an
(A) an altemator
a:ris fxed to the rotor with
respect to a s;mchronously
(B) a transformer
rotating axis
(C) a transmission line (D) angular displacement of the
stator m.m.f, with respect to a
(D) a bus bar synchronously rotating axis
AEIPHE/EE|[I/24136-A 15
Text of page 17
88. For load flow solutions, the 91. In a two-plant system, the load is
quantities specified at load bus are connected to plant 2. Then
(A) loss coeflicients 811,42 and
(A) P and lYl 822 are z-ero
(B) P and Q (B) loss coeflicient .Q1 is non-zero
but q2 and B;22 are znro
(C) P and 6 (C) loss coefficients .Q 1 and Q2
are non-zefo but 822 is zero
(D) Q and lYl
(D) loss coefficients B11 and 822
are non-zero but Q2 is zero
89. In Gauss-Seidel method of power Normally Z bus matrix of a power
flow problem, the number of system is a
iterations may be reduced if the
correction in voltage at each bus is (A) null matrix
multiplied by (B) sparse matrix
(C) full matrix
(A) Gauss constant
(D) unity matrix
(B) acceleration conatant
93. A water boiler at home is switched on
(C) blocking factor to the AC mains supplying power
at 23OVl5OHz. The frequency of
(D) deceleration constant instantaneous power consumed by
the boiler is
(A) 0 Hz
90. For a Y-bus matrix of a 4-bus system (B) 50 Hz
given in per unit, the buses having
shunt elements are (C) 100 Hz
(D) 150 Hz
r-s 2 2.s ol
lz-ro2.s4l
Yu"" = Jl
The powers generated by two plants
2.s 2.s -g 4 |
are 4 = 50 MW and Pz = 40 MW. tf
lo 4 4 -81 the loss coeflicients are
4r = 0 OOl, Bzz =O'OO25
(A) 3 and 4
4z =-0'000s
then the power loss will be
(B) 2 and 3 (A) s's Mw
(Bl 4.s Mw
(C) 1 and 2
(c) 6.s Mw
(D) 1, 2 and 4 (D) 8.s Mw
AEIPHEIEE/\\ 124136-A t7 I P.T.O.
Text of page 18
v
Economic operation of power system A large size synchronous generator-is
is carried out on the basis of protected against overloads by
(A) equal incremental fuel cost (A) over-current relay
(B) equal area criterion (B) mho relay
(C) equal fuel cost (C) temperature-sensitive relay
(D) all units sharing equal power (D) Buchholz relay
99. In central AGC (Automatic Genera-
The knowledge of maximum sag is
tion Control) of a given control area,
essential in determining the
the change (error) in frequency is
(A) ground clearance of the (A) area control error
conductor
(B) volume control error
(B) ma-ximum span of the
conductor (C) non-linear control enor
(C) ma-ximum stress of the (D) optimal control error
conductor
(D) None of the above 1OO. The receiving-end voltage for a long
transmission line under no-load
condition is
97. The term 'self-GMD' is used to
calculate (A) less than the sending-end
voltage
(A) capacitance
(B) more than the sending-end
voltage
(B) inductance
(C) equal to the sending-end
(C) Both (A) and (B) voltage
(D) resistance (D) None of the above
AE IPHE/EE/11/241s6-A 18
Text of page 19
SPACE FOR ROUGH WORX
.
AEIPHEIEEIIl/24136-4 19 lP.r.o.
Text of page 20
v
SPACE TOR ROUGH WORX
-
t
***
AE/PHE/EE /tr/24136-a 20 241-195r4
Text of page 1
& e{--I. :fl- Cq.f<s-Cq.<f \=xl.|-c-=-f .5i
Provisionai Answer Key of OMR based Screening Test for
recruitment to the post of Assistant Engineer (Civil, Mechanical, Electrical, Chemical) Pubtic
Health Engineering Department
held on09.06.2024
(Advt. No.28l2023 dated 31.10.2023)
Subiect: Paper - II (ELECTRICAL ENGINEERING)
Series: A
Marks: 100 Time: 2:00 hours
E
Q.NO. ANS-KEY ANS KEY Q. NO. ANS KEY ANS KEY
1 D 26 D 51 D 76 A
2 C 27 B 52 A 77 C
3 C 28 D 53 A 78 C
4 C 29 B 54 B 79 D
5 D 30 C 55 A 80 C
6 C 31 A 56 B 81 B
7 D 32 D 51 A 82 C
8 B 33 D 58 B 83 A
9 D 34 D 59 B 84 A
10 B 35 A 60 B 8s A
11 A 36 D 61 C 86 C
12 D 37 A 62 C 87 C
13 D 38 C 63 C 88 B
14 C 39 B 64 A 89 B
15 D 40 B 65 B 90 C
l6 C 41 B 66 C 91 A
t7 D 42 D 67 C 92 C
18 D 43 C 68 C 93 C
19 D 44 C 69 B 94 C
20 A 45 D 70 D 95 A
21 D 46 t] 71 A 96 A
22 A 47 A 72 B 91 ti
23 B 48 A 73 C 98 C
24 A 49 A l4 B 99 A
25 A 50 C 75 B 100 B
T"---
Text of page 2
^& =ry-=r-r cq.t<5-cr5:r<f iryf<:=I-Ter
Provisional Answer Key of OMR based Screening Test for
recruitment to the post of Assistant Engineer (Civil, Mechanical, Electrical, Chemical) Public
Health Engineering Department
held, on 09.06.2024
(Advt. No.28l2023 dated 31.10.2023)
Subiect: Paper - II (ELECTRICAL ENGINEERING)
Series : B
Marks: 100 Time: 2:00 hours
Q. NO. ANS KEY Q.NO. ANS KEY Q.NO. ANS-KEY Q,NO. ANS_KEY
1 A 26 A 51 D 76 B
2 B 27 B 52 A 77 A
) C 28 C 53 B 78 A
4 B 29 A 54 A 79 A
5 B 30 B 55 A 80 C
6 A 31 D 56 D 81 D
7 C 32 C 57 B 82 A
8 C )) C 58 D 83 A
9 D 34 C 59 B 84 B
l0 C 35 D 60 C 85 A
1l B 36 C 61 A 86 B
12 C 37 D 62 D 87 A
l-) A 38 B 63 D 88 B
14 A 39 D 64 D 89 B
l5 A 40 B 65 A 90 B
16 C 41 A 66 t) 91 C
17 C 42 D 67 A 92 C
18 B 43 D 68 C 93 C
l9 B 44 C 69 B 94 A
20 C 45 D 70 B 95 B
21 A 46 C 71 B 96 C
22 C 47 D 72 D 97 C
23 C 48 D 73 C 98 C
24 C 49 D 14 C 99 B
25 A 50 A 75 D 100 D
A"--^
Text of page 3
q-=r=r cq..|-=r5-iE:=f=rf qt-C.El*r€r
Provisional Answer Key of OMR based Screening Test for
recruitment to the post of Assistant Engineer (Civil, Mechanical, Electrical, Chemical) Public
Health Engineering Department
held on 09.06.2024
(Advt. No.28l2023 dated 31.10.2023)
Subiect: Paper - II (ELECTRJCAL ENGINEERJNG)
Series : C
Marks: 100 Time: 2:00 hours
I
Q.NO. ANS-KEY Q. NO. ANS KEY Q. NO.
I B 26 C 51 A 76 C
2 D 27 C 52 C 77 D
J C 28 C 53 C 78 D
4 C 29 B 54 C 79 D
5 D 30 D 55 A 80 A
6 B 31 A 56 A 81 D
7 A 32 B 57 B 82 A
8 A -) -) C 58 C 83 B
9 A 34 B 59 A 84 A
10 C 35 B 60 B 85 A
11 D 36 A 61 D 86 D
12 A C 62 C 87 B
l3 A 38 C 63 C 88 D
14 B 39 D 64 C 89 B
15 A 40 C 65 D 90 C
16 B 41 B 66 C 91 A
17 A 42 C 67 D 92 D
18 B 43 A 68 B 93 D
19 B 44 A 69 D 94 D
20 B 45 A 10 B 95 A
21 C 46 C 71 A 96 D
22 C 47 C 72 D 97 A
23 C 48 B 73 D 98 C
A 49 B 74 C 99 B
IJ B 50 C 75 D 100 B
'au"-"
Text of page 4
A q-=r-r <Gryf-<5-<a-=l-f qtc=I-tar
swE
-to
Provisional Answer Key of OMR based Screening Test for
recruitment to the post of Assistant Engineer (Civil, Mechanicalo Electrical, Chemical) Public
Health Engineering Department
held on 09.06.2024
(Adrt. No.28/2023 dated 31.10.2023)
Subiect: Paper - II (ELECTRJCAL ENGINEERING)
Series : D
Marks: 100 Time: 2:00 hours
Q. NO. ANS KEY Q. NO. ANS-KEY Q. NO. ANS KEY Q. NO. ANS,KEY
1 D 26 B 51 A 76 A
2 A 27 A 52 B 77 B
3 B 28 A 53 C 78 C
4 A 29 A 54 B 79 A
5 A 30 C 55 B 80 B
6 D 3l D 56 A 81 D
1 B .12 A 57 C 82 C
8 D 33 A 58 C 83 C
9 B 34 B 59 D 84 C
l0 C 35 A 60 C 85 D
11 A 36 B 61 B 86 C
12 D 31 A 62 C 87 D
13 D 38 B 63 A 88 B
14 D 39 B 64 A 89 D
15 A 40 B 65 A 90 B
16 D 41 C 66 C 91 A
17 A 42 C 67 C 92 D
18 C 43 C 68 B 93 D
t9 B 44 A 69 B 94 C
20 B 45 B 70 C 95 D
21. B 46 C 71 A 96 C
22 D 47 C 72 C 97 D
23 C 48 C 73 C 98 D
24 C 49 B 74 C 99 D
25 D 50 D 75 A 100 A
'dd---^Page 1 of 20
Source: Assam Public Service Commission. Question paper published by Assam Public Service Commission.