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RSMSSB 2019: Junior Scientific Assistant, Ballistics (code 73)

  • Date: 21 September 2019
  • Paper code: 73
  • Series: master
  • Language: Bilingual
  • 16 pages
RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 1 of 16
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1. Please            fill your Roll Number in O.M.R. Sheet Candidate will themself be                      for
                    No.
                2. At the start of the examination before attempting the question paper               check your test booklet and OMR Answer
                    Sheet and ensure that :
                * The serial numbers of test booklet and OMR answer sheet are same.
                * All pages of test booklet and OMR answer sheet are                              All           from S.No. 1 to last S.No.
                    are printed and pages from S.No. to last S. No.                        in the question booklet.
                In case of any discrepancy I defect the candidate should                     report the matter to the 1nu1!ml::nor
                of test booklet and OMR answer sheet. No claim I objection in this regard will be entertained
                of examination. Candidate will be liable for it.
                3. Answer all questions.
                4. All questions carry equal marks.
                5. Only one answer is to be            for each question.
                6. If more than one answers are marked, it would be treated as
                1. Each question has four alternative responses marked serially as (A.),                                              one circle
                    or bubble indicating the correct answer on the Answer Sheet using                                 PEN.
                8. Use of Mobile Phone/Biuetooth Devices or any other electronic gadget in the examination hall is strictly ncnnin,,t,.rl
                    If any such prohibited material found with any candidate, strict action will be taken against him/her as per rule.
                9. If there is any sort of ambiguity/mistake either of printing or factual nature in Hindi and English Version of the
                    the English Version will be treated as standard.
                wa,rnirln : If a candidate is found copying or if any unauthorized material is found in his/her possession, F.i.R. would be
                                  him/her in the Police Station and he/she would liable to be prosecuted under Section 3 of the
                Pm!v~!,t.lc!n of Unfair means          1992 and Board Regulations. Board may also debar him/her permanently from all
                future examination of the Board.


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(2206) ]   32           (2206) ]
RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 2 of 16
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1                                                          ?                                        ?




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       (C)

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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 3 of 16
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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 4 of 16
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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 5 of 16
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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 6 of 16
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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 7 of 16
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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 9 of 16
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x+
                                                                                                  +            + ex -t- d =           -t- 3   x+                       ==?
                                                                                                                                 2-x

                                                                                                                                     x+
                                                                                                      +            +ex+ d =             +3    x+           X      ~·


                                                                                                                                     2-x           -4

                                                                                              0                                                            1
                                                                                                                                                           -2

   (A)~~
                                                                                           11 +X                      1
                                                                                                          +x                   = 0,
                                                                                           11                        +

                                                                                                                   x satisfying                         are-

                                                                                                +x
                                                                                    ~             1       1+ X                  =0,
                                                                                                  1            1     1+
   (A)                        x)                 -d ( y+x ) =x 2 +smx
                                                                   .
                                                 dx                                        ~ f!J:i"l<b (Of c6f

                                                                                                      1, 3                                                      , -3
            d
   (C)     -(cosx+        x)=x+y                                                                          -3                                               0,    3
           dx




                                                                                                                          l~
                                                                                                                                 0
                                   is a                        ?                                                                 3  OJ lS.
                                                                                                                                    0
                                                                                                                                                        to -
                                                                                                                                 0 -5
   Rik'lR<lfula it -e- ~ ~ ~                   t ?


                                                                                    ~l~ ~J
                                                                                                          0
           dy   2
           - - x y=       X                           +x2y =       y                                      3
           dx                                    dx                                                                                   ~t
                                                                                                          0

           (l + y) dy +   x=O                         + y(y + x) = x   v                      1                                                            2
  (C)                                                                  _.._
                  dx                             dx                                           3                                                            4

(2206) ]                                  16                                  [   (2206)                                                            7                        [   T
RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 10 of 16
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-       1).
                                                                                                 1 '                                        =           +        -4        EJR

                                                                                                                                                 x~2                              >2
                                                                                             ~             ~                                      ~2                              <2

                                                                            +    +   +       =0
                                                                            +    +           =0
                                                                                                                     ~               =                 -4    XEJR      ~

                                                                                                                            x::s;2                     x>
                                                                                                                                                       x<
                                               1)
           a+fj+               =0                                        a+fj=l

           1 1
           -+-=                                                             =1
           a f3                                                                                                             •uuvu~;u f(x)=Jxl+lx-11              is-
                                                                                                                     (A)                  at x = 0                         at x =
                               a cone                    lS                                                curve
                                                                                                                                          at x                             at x = 0
                                        + by 2 + cz 2 = 1,        +      + nz = p is -
                                                                                                                                                             x=
   i3tr ~~   C!5T                      ~ !lM            ~ if{         t mrr iiiT S~Rra1&1 ~                                               at X= 0           X=

      +      +nz=               -6~t,t-                                                                              ~ f(x) =I xI+ I x-11 ~­
           p2 (ax
                        2
                            + by 2 +cz 2 ) = (lx+        +                                                           (A)    X =   0      ~ ~ X = l if{

                    2          2       2                          2                                                         x=lm                   x=Om
           p(ax + by +cz ) =                        +   + nz)
                                                                                                                            x=Od"trrx= 1m
   (C)        (ax +by +cz ) =
                        2          2       2
                                                    +    +                                                                  x=Od"trrx= 1m

           p(ax2 +by 2 +cz 2 ) = (lx+my+nz)
                                                                                                                                                                            au
                                                                                                                                                                           x- +
                                                                                                                                                                                       au is-
                                                                                                                                                                            ax
  ~ x+y+z=l ~                                       ~C!5T~..,..,..t-

                                                                                                                     ~      u=
             1, 1)                                                      (j,3'3)
                                                                                                                            tanu                                            tan

                                                                                                                            cos                                                   2u


(2206) ]                                                     18                                        [           (2206)
RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 11 of 16
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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 12 of 16
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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 14 of 16
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?


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one            ?
                   ?



          Ac
RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 15 of 16
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RSMSSB 2019 question paper, Junior Scientific Assistant 2019, Ballistics (code 73), page 16 of 16
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centres




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  (A)




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           0
(2206) ]                       30   (2206)   31   T
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Source: Rajasthan Staff Selection Board. Question paper published by Rajasthan Staff Selection Board.