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Pulse Modulation Techniques Questions and Answers

Answer: A

The filter must pass the whole signal band while rejecting the first spectral repeat, so its cut-off sits between the signal's top frequency and half the sampling rate. That window is exactly what oversampling widens, which is why a higher rate makes the filter cheaper. Cutting off above half the rate would admit the repeat, and cutting below the signal band would discard part of the signal. A requirement bracketed from both sides always has a window whose width is itself a design variable.

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Answer: B

Sampling well above Nyquist moves half the sampling rate far above the signal band, so the filter has a wide transition region and need not be steep. Word length is a separate matter, quantisation noise per unit bandwidth is unchanged by the rate alone, and the signal's bandwidth is a property of the signal. Buying an easier filter with a faster clock is a trade that became attractive as digital circuitry got cheap and precision analogue filters did not.

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Answer: C

A hiss present at all levels and unaffected by them points at quantisation noise, which is generated inside the coder and rides along with the signal. Lost synchronisation would render the speech unintelligible rather than merely hissy. Path noise would be removed by the regenerators unless it were severe enough to cause errors, which sound like clicks. And a low filter cut-off would dull the speech rather than add noise. Asking whether an impairment varies with signal level separates coder faults from channel faults at once.

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Answer: D

Clicks that track path quality are bit errors: a corrupted bit changes a sample's value abruptly and the decoder reproduces that jump faithfully. Quantisation noise is a steady hiss unaffected by the path. Slope overload distorts loud, fast passages rather than producing isolated clicks. And aliasing produces spurious tones. Whether a symptom follows the path or follows the signal is the single most informative observation about a digital link. The parameter that varies and the parameter that does not are worth naming before any substitution is attempted.

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Answer: A

Everything wrong and nothing missing is the signature of a slot count offset: the receiver is decoding each slot as its neighbour. A failed sensor would corrupt one channel only. Narrow filters would dull every reading without misrouting any. And a word length error would scale the values rather than swap them. A fault that affects every channel equally and in the same way almost always lies in the framing rather than in the channels. Most errors on this topic come from carrying a result across from a neighbouring scheme where it does not hold.

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96.

A delta modulated link reproduces quiet passages cleanly but distorts loud, high-pitched sounds. Which explanation fits?

Answer: B

Loud and high-pitched together means steep, so the input's slope is exceeding the step size times the clock rate. Granular noise is the opposite failure and shows up on quiet or steady passages. Aliasing would produce spurious tones rather than distortion tracking loudness and pitch. And bit errors would not correlate with the signal at all. The two delta modulator defects can be told apart purely by which passages they spoil, which is why the symptom description is enough to name the cure.

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Answer: C

A larger step raises the slope the staircase can follow, and a faster clock would do the same; adaptive delta modulation varies the step automatically for exactly this reason. A narrower filter would dull the output without helping the tracking. A longer hold does not enter into it. And a slower clock would make matters worse by reducing the slope limit further. Once a limit is expressed as a product, every factor in it is a candidate remedy, and the cheapest one wins.

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Answer: D

A step too small causes slope overload on fast signals, and a step too large causes granular noise on steady ones, so the parameter has an optimum rather than a direction of improvement. The other pairings are real trades elsewhere in the system but not the one the step size decides. Whenever a parameter is squeezed from both sides, adaptive control of it is the natural next step, and that is exactly how adaptive delta modulation came about. Framing the question as which quantity the change acts upon makes the answer follow without calculation.

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Answer: A

Width modulation needs only a low-pass filter, since its average value is the message - which is why it appears in the simplest control applications. Code modulation needs a decoder and framing, adaptive delta modulation needs a matched adaptive decoder, and position modulation needs slot timing. Ranking schemes by receiver complexity often reverses the ranking by performance, and which ranking matters depends entirely on where the equipment has to sit.

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Answer: B

Width modulation is the answer, for the same reason as before: a filter is the whole demodulator. The three alternatives all need decoders, timing recovery or adaptation logic at the far end. Where one end of a link must be cheap and the other may be expensive, the scheme chosen should put the complexity at the expensive end, and this is the clearest example of that principle in the pulse family.

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