Match List I with List II and select the correct answer using the codes given below :
| List I | List II |
|---|---|
| (a) TDM | (i) Frequency detector |
| (b) FM | (ii) Envelope detector |
| (c) AM | (iii) Sensitive to propagation delay |
| (d) FDM | (iv) Non-sensitive to propagation delay |
MH SET - 2021, SET Exam - 2021,
Answer: A
The correct code is (a)-(iii), (b)-(i), (c)-(ii), (d)-(iv).
TDM interleaves the channels in time slots, so the receiver must stay synchronised with the transmitter and the system is sensitive to propagation delay (iii). FM is demodulated by a frequency detector or discriminator (i). AM is demodulated by an envelope detector (ii). FDM separates channels by frequency, so all of them travel simultaneously and a delay in the path does not mix them up (iv).
The other codes swap the detectors between AM and FM, or assign delay sensitivity to the frequency-division system.
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