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Acid Base and Redox Equilibria Questions and Answers

21.

Match the List - I with List - II and identify the correct answer from the given codes :

List - I (Thermodynamic Variables) (Symbols have their usual meanings.)List - II (Expression)
(a) \(\Delta G\)i. \(\Delta E + P\Delta V\)
(b) \(\Delta G^{\circ}\)ii. \(- nFE^{\circ}\)
(c) \(\Delta S\)iii. \(RT \ln \frac{V_1}{V_2}\)
(d) \(\Delta H\)iv. \(nR \ln \frac{V_2}{V_1}\)

Codes : (a) (b) (c) (d)

Exam Year(s)

UGC NET - 2013,

Answer: B

The correct matching is a-iii, b-ii, c-iv, d-i, which is code B. The free energy change for an ideal gas at constant temperature is RT ln(V1/V2), so (a) goes with iii. The standard free energy change is related to the standard cell potential by the expression minus nFE°, so (b) goes with ii. The entropy change on isothermal expansion is nR ln(V2/V1), so (c) goes with iv. The enthalpy change is the energy change plus PΔV, so (d) goes with i.

Options A, C and D each pair at least one of these variables with the wrong expression.

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22.

In the redox reaction given below, which one of the substrates in forward reaction is oxidized ? \(\mathrm{2Fe^{3+} + H_{2} \rightarrow 2Fe^{2+} + 2H^{+}}\)

Exam Year(s)

UGC NET - 2013,

Answer: B

Hydrogen is oxidized. In the forward reaction H2 goes to H+, so its oxidation state rises from 0 to +1, which means it loses electrons. Iron goes from Fe3+ to Fe2+, a fall from +3 to +2, so Fe3+ is reduced and acts as the oxidizing agent.

H+ and Fe2+ are products and not substrates of the forward reaction, so they cannot be what is oxidized. Fe3+ is a substrate but it is the one reduced. The substrate that is oxidized is H2, option B.

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23.

pE values in water range from approximately

Exam Year(s)

UGC NET - 2013,

Answer: B

The pE values in water range from about -12 to 25, option (B). The pE is the negative logarithm of the electron activity and measures the oxidising or reducing tendency of the water. Highly reducing waters, for example in anoxic sediments, have a strongly negative pE, and oxygen-rich waters have a high positive one, and the range stretches across about 37 units. The ranges in options (A), (C) and (D) are far narrower and do not cover both extremes.

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24.

A 50 ml solution of pH = 1 is mixed with a 50 ml solution of pH = 2. The pH of the mixture will be nearly

Exam Year(s)

UGC NET - 2014,

Answer: B

The hydrogen ion concentration of the mixture is the total moles of H+ divided by the total volume, and the pH is nearly 1.26.

\[ [H^{+}] = \frac{50 \times 0.1 + 50 \times 0.01}{100} \]\[ = 0.055\ M \]\[ pH = -\log(0.055) \approx 1.26 \]

Averaging the two pH values would give 1.5, which is wrong because pH is logarithmic, and the other options do not follow from the mole balance.

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25.

The solubility product of the following type of reaction : \(Al(OH)_{3} \rightarrow Al^{3+} + 3OH^{-}\) is

Exam Year(s)

UGC NET - 2014,

Answer: C

For the dissolution Al(OH)3 giving Al3+ and 3 OH-, the solubility product is the product of the ion concentrations, each raised to its stoichiometric coefficient, so Ksp equals the concentration of Al3+ times the cube of the OH- concentration. The solid does not appear in the expression.

Option A includes the solid and does not cube OH-. Option B writes 3OH- as a single term instead of raising the concentration to the third power. Option D leaves out the cube. Only option C gives the correct form.

A pure solid has a fixed activity and so is left out of the expression, and the coefficient of each ion appears as the power of its concentration, which is the general rule used for any sparingly soluble salt.

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