A frame in video transmission system has 800 × 400 pixel grid with 64 intensity levels per pixel. The transmission system transmit 360 picture frames per second. The data rate of the system is :
MH SET - 2019, SET Exam - 2019,
Answer: C
The data rate is 691.2 Mb/s.
64 intensity levels need \(\log_{2}64 = 6\) bits per pixel.
\[ \begin{aligned} \text{bits/frame} &= 800 \times 400 \times 6 \\ &= 1{,}920{,}000 \\ \text{rate} &= 1.92 \times 10^{6} \times 360 \\ &= 691.2\ \text{Mb/s} \end{aligned} \]
1382.4 Mb/s is double the answer, as if 12 bits per pixel were used, and 3686 Mb/s and 7372 Mb/s come from using 32 or 64 per pixel instead of the 6 bits.
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