Data Interpretation Questions and Answers

Answer: A

Total sales of branch B6 = 70 + 80 = 150 thousand.

Total sales of branch B3 = 95 + 110 = 205 thousand.

Required percentage = \(\frac{\text{Sales of B6}}{\text{Sales of B3}} \times 100\)

= \(\frac{150}{205} \times 100 \approx 73.17\)%.

Answer: B

Correct answer: 80,000

Read the 2018 series across all six branches and add.

\[80 + 75 + 95 + 85 + 75 + 70 = 480 \text{ thousand}\]

Divide by the six branches:

\[\frac{480}{6} = 80 \text{ thousand} = 80{,}000\]

Note the units: the chart is in thousands, so the average of 80 on the chart is 80,000 books.

Answer: A

Correct answer: B3

Reading the 2019 series across the six branches gives 105, 65, 110, 95, 95 and 80 thousand. The largest of these is 110, recorded by B3.

B3 also led in 2018 with 95 thousand, so it is the strongest branch in both years.

Answer: B

To find the total production of type B cars, we need to sum the values in the 'B' column.

Total Production of B = 150 + 160 + 170 + 180 + 190 + 200

This is an arithmetic progression. Sum = \(\frac{n}{2}(a+l) = \frac{6}{2}(150+200) = 3 \times 350 = 1050\).

Answer: A

We need to calculate the percentage increase for each car type using the formula: \(\frac{\text{Final Value} - \text{Initial Value}}{\text{Initial Value}} \times 100\).

• A: \(\frac{160-100}{100} \times 100 = 60\)%
• B: \(\frac{200-150}{150} \times 100 = \frac{50}{150} \times 100 \approx 33.33\)%
• C: \(\frac{170-120}{120} \times 100 = \frac{50}{120} \times 100 \approx 41.67\)%
• D: \(\frac{230-180}{180} \times 100 = \frac{50}{180} \times 100 \approx 27.78\)%

The maximum percentage increase is for car type A.

Answer: B

Read the 2018 row of the table and average the five figures.

\[ 140 + 180 + 150 + 210 + 230 = 910 \]

\[ \frac{910}{5} = 182 \text{ thousand} \]

Answer: B

The number is 264.

Mathematics teachers are 22% of all teachers.

\[ 22\% \text{ of } 1600 = \frac{22}{100} \times 1600 = 352 \]

The male to female ratio is 3 : 1, so males are three of every four mathematics teachers.

\[ \frac{3}{4} \times 352 = 264 \]

There are 264 male mathematics teachers. The option 352 is all the mathematics teachers, 88 is the female share (one quarter of 352) and 176 is half of them.

Answer: C

The maximum increase was in hospital A.

The change in the number of patients each month is new admissions minus discharges. Adding August, September and October:

• A: \((80 - 56) + (64 - 78) + (87 - 69) = 24 - 14 + 18 = 28\)
• B: \(15 + 26 - 15 = 26\)
• C: \(17 - 19 - 3 = -5\)
• D: \(-11 + 14 + 14 = 17\)

Hospital A's net increase of 28 is the largest. B is close at 26, C actually fell, and D rose by 17. November is outside the period asked about.

Answer: C

The angle for Mathematics is 86.4°.

The total of all marks is 72 + 84 + 96 + 80 + 68 = 400. A sector's angle is its share of 360°:

\[ \theta = \frac{96}{400} \times 360^\circ = 86{\cdot}4^\circ \]

75.6° is the angle for Hindi (84 marks), 72° would be 80 marks out of 400, which is Science, and 64.8° is the angle for English (72 marks).

Answer: D

The correct statement is Ten children do not like any fruit given in the table.

Add the children in the table:

\[ 28 + 26 + 44 + 14 + 28 = 140 \]

150 children were asked, so 150 − 140 = 10 children named some other fruit.

The other statements fail on the numbers. Apple (28) and Guava (26) are not equal. Grapes minus Banana is 28 − 14 = 14, not 16. Mangoes and Banana together make 44 + 14 = 58, while twice Guava is 2 × 26 = 52, so that is not 'two times' either.