Problems on Ages Questions and Answers

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21.

The average of the ages of Sumit, Krishna and Rishabh is 43 years and the average of the ages of Sumit, Rishabh and Rohit is 49 years. If Rohit is 54 years old, what is Krishna'a age ?

A.30 years
B.36 years
C.42 years
D.48 years

Answer: B

Let present ages of Sumit = \(w\), Krishna = \(x \), Rishabh = \(y\) and Rohit = \(z\) , then

\(w+x+y = 43*3 = 129 ..(i)\)

\(w+y+z = 49*3 = 147 ..(ii)\)

Subtracting (i) from (ii),
\((w+y+z) - (w+x+y)=147 -129 , z- x =18 ..(iii)\)

Given Rohit's age => z = 54, so from (iii), x = 54-18 = 36

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22.

The present average age of a family of five members is 26 years. If the present age of the youngest member in the family is ten years, then what was the average age of the family at the time of the birth of the youngest member ? (Assume no death occurred in the family since the birth of the youngest

A.18 years
B.19 years
C.20 years
D.21 years

Answer: C

Present total age of the members = 26(5) = 130 years

Present age of the youngest member = 10 years
Present total age of the remaining four members = 130 - 10 = 120 years

Their average age at the time of the birth of the youngest member = \(\frac{120-(4*10)}{4}\)

= 30 - 10 = 20 years

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23.

Rohit is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age of Rohit

A.31.5 years
B.32.5 years
C.22.5 years
D.24.5 years

Answer: D

lets Rahul's age is \(x\) years

Then Rohit's age \(=(x-7)\) years

so, \(\frac{(x-7)}{x}=\frac{7}{9}\)

\(\Rightarrow \) \(9x-63=7x\)

\(\Rightarrow\) \(2x=63\)

\(\Rightarrow\) \(x=31.5\)

\(\therefore \) Rohit's age \(31.5-7=24.5\) years

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24.

Father is aged three times more than his son. After 8 years, father would be two and a half times of son's age. After further 8 years, how many times would father be of son's age?

A.2 times
B.3 times
C.4 times
D.5 times

Answer: A

Assume that son's present age \(= x \)

Then, father's present age = \(3x+x=4x\)

After \(8\) years, father's age \(=2\tfrac{1}{2}\) times of son's age.

\(\Rightarrow\) \((4x+8)=2\tfrac{1}{2}(x+8)\)

\(\Rightarrow\) \(4x+8=\tfrac{5}{2}(x+8)\)

\(\Rightarrow\) \(8x+16=5x+40\)

\(\Rightarrow\) \(3x=40-16=24\)

\(\Rightarrow\) \(x=\frac{24}{3}=8\)

After further \(8\) years,

Son's age \( =x+8+8=8+8+8=24\)

Father's age \(=4x+8+8=4×8+8+8=48\)

Father's age/Son's age \(=\frac{48}{24}=2\)

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25.

Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?

A.11/P + 6
B.P/11 + 6
C. 11/P - 6
D.P/11 - 6

Answer: A

Let Ben’s age now be \(B \)

Anita's age now be \(A\)

\((A - 6) = P(B - 6)\)

But \(A\) is 17 and therefore, \(11 = P(B - 6)\)

\(\Rightarrow 11/P = B-6\)

\(\Rightarrow (11/P) + 6 = B\)

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26.

Raju got married 8years ago. His present age is 6/5 times his age at the time of his marriage Raju's sister was 10years younger to him at the time of his marriage. The present age of Raju's sister is ?

A.37
B.38
C.39
D.40

Answer: B

Let Raju's age at the time of his marriage = \(x\) years

Then from given data,

\(\Rightarrow x +8=\frac{6}{5}x\)
\(x=40\)

Since got married 8 years ago, his present age = 48

His sister is 10 years younger => 48 - 10 = 38 years.

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27.

A man is \(24\) years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?

A.20
B.21
C.22
D.23

Answer: C

Let present age of the son \(= x \) years

Then, present age the man \(=(x+24)\) years

Given that, in \(2\) years, man's age will be twice the age of his son

\(\Rightarrow\) \((x+24)+2=2(x+2)\)

\(\Rightarrow\) \(x=22\)

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28.

A mother said her daughter , " I was as old as you are at present at the time of your birth. " If the mother age is 38 now, the daughter age 5 years back was ?

A.14
B.19
C.33
D.38

Answer: A

Let the son's present age be \(x\) years .

Then, \( (38 - x) = x \)

\(=> x= 19\)

Son's age 5 years back = (19-5) = 14 yeara

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29.

When Raj Tarun was born, his father was 32 years older than his brother and his mother was 25 years older than his sister. If Raj Tarun's brother is 6 years older than Raj Tarun and his mother is 3 years younger than his father, how old was Raj Tarun's sister when Raj Tarun was born ?

A.5
B.10
C.15
D.8

Answer: B

Raj Tarun's age = 0 when he was born.
Then, given his brother is 6 years old.
Then his father is 6 + 32 = 38 when Raj Tarun was born
And his mother is 3 years yonger than his father => so his mother was 35 years old when Raj Tarun was born
and his sister is 25 year younger than his mother
so Raj Tarun's sister was 10 years old when Raj Tarun was born.

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30.

The sum of the ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child ?

A.2 years
B.4 years
C.6 years
D.8 years

Answer: B

Let the age of the youngest child is '\(x \)' years.
Then the child elder than the yongest is '\(x + 3\)' yrs
Since each have 3yrs difference upto 5 children
And given that,

\(\Rightarrow x +x +3 + x+6 +x+9 + x+12 = 50\)

\(\Rightarrow 5x+30=50\)

\(\Rightarrow x= 4\) years.

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