Data Sufficiency Questions and Answers

Answer: D

Correct answer: Both 1 and 2 are sufficient

Statement 1 gives last year’s figure of 2935 and statement 2 the ratio of 1.2, so this year’s sales are 2935 x 1.2 = 3522. Each is useless alone - a base without a ratio, or a ratio without a base - and together they give a single number.

Answer: A

From 1, we conclude that there are 16 students and 11 boys taller than Shravan.

This implies that there are 5 girls taller than Shravan.

In 2, Shravan's rank from the bottom is mentioned and to ascertain the number of girls taller than him, we need to know his rank from the top for which the number of students in the class is required, which is not given.

Answer: D

Correct answer: Neither 1 or 2 is sufficient

Statement 1 fixes S and Q at the two ends but leaves P, R and T to fill the three middle places in any order. Statement 2 gives only a relative position for T and R. Together they still admit more than one arrangement of the middle three, so the central building cannot be named.

Answer: C

I. In 'right or wrong' and 'he is right', the common word is 'right' and the common code word is 'nik'. So 'nik' means 'right'. In 'right or wrong' and 'that is wrong', the common word is 'wrong' and the common code word is 'te'. So, 'te' means 'wrong'.

Thus, in 'right or wrong', 'sa' is the code for 'or'. II. In 'that right man' and 'this or that', the common word is 'that' and the common code word is 'pa'. So, 'pa' means 'that'. In 'this or that' and 'tell this there', the common word is 'this' and the common code word is 'ne'. So, 'ne' means 'this'. Thus, in 'this or that', 'sa' is the code for 'or'.

Answer: D

From the two statements given in 1, the code for the only common word 'beautiful' can be determined.

From the two statements given in 2, the code for the only common word 'red' can be determined.

In I and II, the common words are 'rose and 'flower' and the common code words are 'de' and 'la'. So, the code for 'flower' is either 'de' or 'la'.

Answer: A

From 1, we have: P > M, P > K, A > P.

Thus, A > P > M > K or A > P > K > M. So, Akash is the heaviest.

From 2, we have: P > M, A > M, M > K.

Thus, A > P > M > K or P > A > M > K. So, either Akash or Prabhakar is the heaviest.

Answer: D

From 1, we know that L is T's brother and J's husband. Since L is the only son of his parents, T is L's sister.

From 2, we know that K is L's daughter.

Thus, from 1 and 2, we conclude that T is the sister of K's father i.e. T is K's aunt.

Answer: C

From 1, we conclude that weight of each pole = (4x5) kg = 20 kg.

So, total weight of 10 poles = (20 x 10) kg = 200 kg.

From 2, we conclude that:

Weight of each pole = (weight of 3 poles) - (weight of 2 poles) = 20 kg.

So, total weight of 10 pojes = (20 x 10) kg = 200 kg.

Answer: C

Correct answer: Either 1 or 2 is sufficient

The question asks how A is related to B, and since B is A’s brother the answer turns entirely on A’s sex. Statement 1 calls A the sister of C, and statement 2 makes A the wife of E; each establishes that A is female and therefore B’s sister. Either alone will do.

Answer: A

From I, we have: B > T, B > C, V > B. Thus, V is heavier than each one of B, T and C. But V is not the heaviest. So, E is the heaviest.

Thus, we have the order. E>V>B>T>C or E>V>B>C>T. Clearly, B is third from the top.