Data Interpretation Questions and Answers

Answer: B

Let the Cost Price (CP) be x. The Marked Price (MP) is 20% above CP. So, MP = 1.20 * CP.

180 = 1.20 * CP => CP = 180 / 1.2 = Rs. 150.

The cost of paper is 25% of the total cost price.

Cost of paper = 25% of 150 = 0.25 * 150 = Rs. 37.50.

Answer: A

Total sales of branch B2 for both years = 75 + 65 = 140 thousand.

Total sales of branch B4 for both years = 85 + 95 = 180 thousand.

The required ratio is 140 : 180.

Dividing both by 20, we get the simplified ratio 7 : 9.

Answer: A

Total sales of branch B6 = 70 + 80 = 150 thousand.

Total sales of branch B3 = 95 + 110 = 205 thousand.

Required percentage = \(\frac{\text{Sales of B6}}{\text{Sales of B3}} \times 100\)

= \(\frac{150}{205} \times 100 \approx 73.17\)%.

Answer: B

Correct answer: 80,000

Read the 2018 series across all six branches and add.

\[80 + 75 + 95 + 85 + 75 + 70 = 480 \text{ thousand}\]

Divide by the six branches:

\[\frac{480}{6} = 80 \text{ thousand} = 80{,}000\]

Note the units: the chart is in thousands, so the average of 80 on the chart is 80,000 books.

Answer: A

Correct answer: B3

Reading the 2019 series across the six branches gives 105, 65, 110, 95, 95 and 80 thousand. The largest of these is 110, recorded by B3.

B3 also led in 2018 with 95 thousand, so it is the strongest branch in both years.

Answer: B

To find the total production of type B cars, we need to sum the values in the 'B' column.

Total Production of B = 150 + 160 + 170 + 180 + 190 + 200

This is an arithmetic progression. Sum = \(\frac{n}{2}(a+l) = \frac{6}{2}(150+200) = 3 \times 350 = 1050\).

Answer: A

We need to calculate the percentage increase for each car type using the formula: \(\frac{\text{Final Value} - \text{Initial Value}}{\text{Initial Value}} \times 100\).

• A: \(\frac{160-100}{100} \times 100 = 60\)%
• B: \(\frac{200-150}{150} \times 100 = \frac{50}{150} \times 100 \approx 33.33\)%
• C: \(\frac{170-120}{120} \times 100 = \frac{50}{120} \times 100 \approx 41.67\)%
• D: \(\frac{230-180}{180} \times 100 = \frac{50}{180} \times 100 \approx 27.78\)%

The maximum percentage increase is for car type A.

Answer: B

Read the 2018 row of the table and average the five figures.

\[ 140 + 180 + 150 + 210 + 230 = 910 \]

\[ \frac{910}{5} = 182 \text{ thousand} \]

Answer: B

The number is 264.

Mathematics teachers are 22% of all teachers.

\[ 22\% \text{ of } 1600 = \frac{22}{100} \times 1600 = 352 \]

The male to female ratio is 3 : 1, so males are three of every four mathematics teachers.

\[ \frac{3}{4} \times 352 = 264 \]

There are 264 male mathematics teachers. The option 352 is all the mathematics teachers, 88 is the female share (one quarter of 352) and 176 is half of them.

Answer: C

The maximum increase was in hospital A.

The change in the number of patients each month is new admissions minus discharges. Adding August, September and October:

• A: \((80 - 56) + (64 - 78) + (87 - 69) = 24 - 14 + 18 = 28\)
• B: \(15 + 26 - 15 = 26\)
• C: \(17 - 19 - 3 = -5\)
• D: \(-11 + 14 + 14 = 17\)

Hospital A's net increase of 28 is the largest. B is close at 26, C actually fell, and D rose by 17. November is outside the period asked about.