Data Interpretation Questions and Answers

Answer: A

The order is Games, Dance, Academic, Music. Averaging the four schools for each activity:

Descending, that is Games, Dance, Academic, Music, which is option A and not the orders in B, C and D.

The question asks for the average number of students, which is taken to be the average of the four percentage figures for each activity, because all the schools are compared on the same percentage scale. Dance has a higher average than Academic only because DS has 30 in dance against 15 in academic, which is why Dance sits between Games and Academic.

Answer: C

Medicine is 104.76% of science. From the chart, medicine is 22% of the 3600 students and science is 21%. As a share of science:

The 3600 cancels out. 56.89% and 73.25% are wrong ratios of other pairs, and 10.76% is the figure with the leading 1 missing.

The question gives the 3600 students, but the ratio of the two groups does not depend on it: 22% of 3600 is 792 and 21% of 3600 is 756, and 792 / 756 = 1.0476, which is 104.76%. The answer is above 100% because the medicine group is larger than the science group.

Answer: D

April's share is 24 per cent. The six bars read 25, 19, 30, 43, 35 and 27, which total 179. April has 43, so \[ \frac{43}{179} \times 100 \approx 24.0\% \] which is 24 to the nearest integer.

15%, 20% and 22% do not match 43 out of 179.

The share is worked out as the April bar over the total of all six bars, so 43 / 179 = 0.240 and the figure is 24 per cent.

Answer: A

The required percentage is about 104 per cent. Hockey players from school A number 125 and badminton players from school B number 120. 125/120 x 100 = 104.17, which is approximately 104 per cent. 96 per cent is the inverse ratio 120/125, and 98 and 102 per cent do not come from these two entries. The question compares two different cells of the table: hockey players in school A (125) and badminton players in school B (120). The ratio 125/120 is 25/24, which is about 1.0417, i.e. 104.17 per cent.

Answer: C

The decrease is 22 6/7 per cent. The graph shows 35 accidents in May and 27 in June, a decrease of 8. The percentage decrease is 8/35 x 100 = 22 6/7 per cent. The other options are computed from other pairs of months: for example 15 4/7 per cent and 27 3/7 per cent do not match 8/35. Percentage decrease is always worked out on the earlier figure, so the base is 35 for May and not 27 for June. Using 27 as the base would give 29 17/27 per cent, which is not an option.

Answer: C

In a pie chart the price of an article is its angle over 360 degrees times the total of 28800. The average price of A and B is J1, with A at 125 degrees and B at 75 degrees: the average angle is 100 degrees, so J1 = 100/360 x 28800 = 8000. The difference of G, at 60 degrees, and C, at 12 degrees, is 48 degrees, so J2 = 48/360 x 28800 = 3840.

\[ J1 - J2 = 8000 - 3840 = 4160 \]

So the value is 4160, option (C). The values 3840 and 5280 are the price of J2 and a wrong average.

Answer: B

The line chart gives the numbers of calculators sold by the five shops as 20, 50, 75, 125 and 100. Their sum is 20 + 50 + 75 + 125 + 100 = 370, and the average over the five shops is 370 / 5 = 74. So the answer is 74, option (B). The values 76, 72 and 78 would need totals of 380, 360 and 390, which do not match the chart, and the point of 125 for the fourth shop is the highest while 20 for the first is the lowest.

Answer: D

Statement I says A's production in Y1 is 50 percent of B's production in Y2. A produced 300 in Y1 and B produced 600 in Y2, and 300 is 50 percent of 600, so statement I is correct. Statement II says the ratio of B's total in Y4 and Y5 to A's total in Y2 and Y3 is 24 : 23. B produced 800 + 400 = 1200 and A produced 600 + 550 = 1150, and 1200 : 1150 = 24 : 23, so statement II is also correct. The question asks for the statement that is NOT correct, and neither statement is wrong, so the answer is Neither I nor II, option (D).

Answer: C

The value of x is 120, which lies between 115 and 125. The total is 2400 students. From the pie chart, school A has 22 % = 528, B has 16 % = 384, D has 17 % = 408 and E has 25 % = 600.

\[ \text{Girls in A} = \frac{6}{11} \times 528 = 288 \]

\[ \text{Girls in E} = 0.60 \times 600 = 360 \]

So the girls from A and E number 288 + 360 = 648. The students from B and D number 384 + 408 = 792, and two thirds of that is 528.

\[ x = 648 - 528 = 120 \]

The other ranges, 95 to 105, 105 to 115 and 125 to 135, do not contain 120.

Answer: B

The percentage is 12%.

The January sales (blue bars) are shirt 3, trouser 5, coat 7, T-shirt 4 and jacket 6, which total 25 million units. Shirts are 3 of those.

\[ \frac{3}{25}\times100=12\% \]

20%, 17% and 25% would need a different shirt figure or total.

The graph is a three-dimensional bar chart with three rows of bars: blue for January, orange for March and grey for May. Only the blue bars are needed here. The values 3, 5, 7, 4 and 6 add to 25, and the share of shirts is 3 out of 25, which is 12%.