An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at p
Answer: C
The bomb strikes the ground 3.33 km from A.
Vertically it starts with no downward velocity, so \[t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2\times1960}{9.8}} = \sqrt{400} = 20\ \mathrm{s}\]
Horizontally it keeps the aircraft's speed, \(600\ \mathrm{km/h} = 166.7\ \mathrm{m\,s^{-1}}\): \[x = 166.7 \times 20 = 3334\ \mathrm{m} \approx 3.33\ \mathrm{km}\]
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