Alligation or Mixture Questions and Answers

Q: A mixture of 60 litres contains milk and water in the ratio 2 : 1. How much water must be added to make the ratio 1 : 2?

Correct answer: 60 litresIn 60 litres divided 2 : 1 there are 40 litres of milk and 20 of water. The milk does not change when water is added - that is the key to every question of this kind. For a final ratio of 1 : 2, the water must be twice the milk, so it must become \( 2 \times 40 = 80 \) litres. The water to add is therefore \[ 80 - 20 = 60 \text{ litres}. \] Checking: the vessel then holds 40 litres of milk and 80 of water, a total of 120 in the ratio 1 : 2. The general method is to identify the quantity that stays constant, express the required ratio in terms of it, and subtract what is already present. Working with the total instead invites error, because the total changes while the milk does not. The same approach handles questions where a quantity is removed rather than added.

Important Instructions

111.

In what ratio should two varieties of sugar of Rs.18 per kg and Rs.24 kg be mixed together to get a mixture whose cost is Rs.20 per kg?

A.1:3
B.3:1
C.1:2
D.2:1

Answer: D

The alligation rule gives the ratio in which two ingredients must be mixed:

\[ \frac{\text{cheaper quantity}}{\text{dearer quantity}} = \frac{\text{dearer} - \text{mean}}{\text{mean} - \text{cheaper}} \]

\[ \frac{\text{Rs. 18 sugar}}{\text{Rs. 24 sugar}} = \frac{24 - 20}{20 - 18} = \frac{4}{2} = \frac{2}{1} \]

The mean of 20 is close to 18, so the cheaper sugar dominates at twice the quantity.

Discuss in Forum

112.

Rajesh has a container which has a mixture of wine and water in it. Wine and water are in the ratio 4:1. Rajesh spills some of the mixture by accident. He then replaces the spilled amount with water of same quantity. But now the wine to water ratio became 3:2. How much water did Rajesh add?

A.3/5
B.1/2
C.1/4
D.2/7

Answer: C

Take the container as 5 units: 4 of wine and 1 of water. Spilling a fraction \( f \) removes that fraction of the wine as well, and the water poured back keeps the total at 5.

\[ \text{wine left} = 4(1 - f) \]

The new ratio 3 : 2 means the wine is now 3 of the 5 units:

\[ 4(1 - f) = 3 \quad\Longrightarrow\quad 1 - f = \frac{3}{4} \quad\Longrightarrow\quad f = \frac{1}{4} \]

So a quarter of the mixture was replaced by water. Spilling removes wine and water in their existing proportion, which is what makes the wine shrink by the factor \( 1-f \).

Discuss in Forum

113.

A mixture of 60 litres contains milk and water in the ratio 2 : 1. How much water must be added to make the ratio 1 : 2?

A.60 litres
B.30 litres
C.40 litres
D.20 litres

Answer: B

Correct answer: 60 litres

In 60 litres divided 2 : 1 there are 40 litres of milk and 20 of water. The milk does not change when water is added - that is the key to every question of this kind. For a final ratio of 1 : 2, the water must be twice the milk, so it must become \( 2 \times 40 = 80 \) litres. The water to add is therefore \[ 80 - 20 = 60 \text{ litres}. \] Checking: the vessel then holds 40 litres of milk and 80 of water, a total of 120 in the ratio 1 : 2. The general method is to identify the quantity that stays constant, express the required ratio in terms of it, and subtract what is already present. Working with the total instead invites error, because the total changes while the milk does not. The same approach handles questions where a quantity is removed rather than added.

Discuss in Forum

114.

To gain profit, a milkman adds 1.5 liter of water to a certain amount of milk. He sells the adulterated milk at Rs.28 per liter and pure milk costs Rs.36 per liter. Find the amount of milk.

A.5.25
B.6
C.5.5
D.5

Answer: A

The water is free, so "no loss" means the revenue from the whole adulterated quantity just covers the cost of the pure milk.

\[ 28(m + 1.5) = 36m \]

\[ 28m + 42 = 36m \quad\Longrightarrow\quad 8m = 42 \]

\[ m = 5.25 \text{ litres} \]

Selling at a price below cost is profitable only because the 1.5 L of water is sold as though it were milk.

Discuss in Forum

115.

A container contains 30 liters of milk. From this container 5 liter of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?

A.18.45 liter
B.23.44 liter
C.17.36 liter
D.21.87 liter

Answer: C

When a fraction of a solution is repeatedly removed and replaced, the original liquid left after \( n \) operations is

\[ A\left(1 - \frac{x}{A}\right)^{n} \]

With \( A = 30 \), \( x = 5 \) and \( n = 3 \):

\[ 30\left(1 - \frac{5}{30}\right)^{3} = 30\left(\frac{5}{6}\right)^{3} \]

\[ = 30 \times \frac{125}{216} = 17.36 \text{ litres} \]

Subtracting \( 3 \times 5 = 15 \) litres would give 15 L, but the later withdrawals remove water as well as milk, so more milk survives than that.

Discuss in Forum

Loading…

Topics

Other Subjects

Tags: Alligation or Mixture Questions and Answers || Alligation or Mixture MCQ Questions and Answers || Alligation or Mixture GK Questions and Answers || Alligation or Mixture GK MCQ Questions || Alligation or Mixture Multiple Choice Questions and Answers || Alligation or Mixture GK || GK on Alligation or Mixture || Quantitative Aptitude Questions and Answers || Quantitative Aptitude MCQ Questions and Answers || Quantitative Aptitude GK Questions and Answers || GK on Quantitative Aptitude

Alligation or Mixture Questions and Answers

Important Instructions

Topics

Other Subjects

About Us

Stay informed about all important Dates & Notifications