Circular Seating Arrangement Questions and Answers

Answer: C

Correct answer: BCD

F sits with only B, so that bench holds exactly those two. A is on bench I and G on bench III. C will not sit with A, E or D, so she must join G on bench III, which leaves D and E to sit with A. The benches are therefore I: A, D, E - II: F, B - III: C, G. Each bench needs a girl: C covers III, so B must be the girl on II, and one of A and D the girl on I - D, since the group of girls named is B, C and D.

C is named a girl; B must be one, because bench II holds only F and B and F is a boy; and D must be one, because bench I holds A, D and E, and E is C’s brother. So B, C and D is the group that is certainly all girls.

Answer: C

Correct answer: G

F sits with only B, so that bench holds exactly those two. A is on bench I and G on bench III. C will not sit with A, E or D, so she must join G on bench III, which leaves D and E to sit with A. The benches are therefore I: A, D, E - II: F, B - III: C, G. Each bench needs a girl: C covers III, so B must be the girl on II, and one of A and D the girl on I - D, since the group of girls named is B, C and D.

C cannot sit with A, E or D, and the F–B bench holds only those two, so the only bench left to her is bench III - where G sits.

Answer: A

Correct answer: Bench I

F sits with only B, so that bench holds exactly those two. A is on bench I and G on bench III. C will not sit with A, E or D, so she must join G on bench III, which leaves D and E to sit with A. The benches are therefore I: A, D, E - II: F, B - III: C, G. Each bench needs a girl: C covers III, so B must be the girl on II, and one of A and D the girl on I - D, since the group of girls named is B, C and D.

Bench II holds F and B alone and bench III holds C and G, so the remaining three - A, D and E - must all be on bench I.

Answer: C

Correct answer: R is second to the left of T

Facing the centre, each girl’s right is the next seat anticlockwise and her left the next seat clockwise. P next to V’s left puts P one seat clockwise of V; R fourth to P’s right puts R two seats clockwise of P. Filling in the rest gives the circle, clockwise, as V → P → S → R → Q → T, with T next to V and so not between Q and S.

Two seats to T’s left - clockwise - brings us to V and then P, not R, so that statement is false. The other three hold: S is next to R’s right, T is next to V’s right, and P is two seats to R’s right.

Answer: C

Correct answer: VT

Facing the centre, each girl’s right is the next seat anticlockwise and her left the next seat clockwise. P next to V’s left puts P one seat clockwise of V; R fourth to P’s right puts R two seats clockwise of P. Filling in the rest gives the circle, clockwise, as V → P → S → R → Q → T, with T next to V and so not between Q and S.

Exchanging P and R gives the circle V, R, S, P, Q, T. Of the pairs offered, only V and T are then neighbours - and they were neighbours before the swap too, since neither of them moved.

Answer: D

Correct answer: To the immediate right of V

Facing the centre, each girl’s right is the next seat anticlockwise and her left the next seat clockwise. P next to V’s left puts P one seat clockwise of V; R fourth to P’s right puts R two seats clockwise of P. Filling in the rest gives the circle, clockwise, as V → P → S → R → Q → T, with T next to V and so not between Q and S.

The seat anticlockwise from V - her right - is T’s, so T sits immediately to V’s right. She is not next to Q’s right, nor between Q and R.

Answer: B

Correct answer: T

Facing the centre, each girl’s right is the next seat anticlockwise and her left the next seat clockwise. P next to V’s left puts P one seat clockwise of V; R fourth to P’s right puts R two seats clockwise of P. Filling in the rest gives the circle, clockwise, as V → P → S → R → Q → T, with T next to V and so not between Q and S.

V’s right is the next seat anticlockwise, and T occupies it. P is on V’s left.

Answer: C

Correct answer: J

J sits between L and F, and G between I and F, so F has J on one side and G on the other, giving the run I – G – F – J – L. H is two seats to J’s left (clockwise), and F sits opposite E, which places the last three. Clockwise the eight seats read I → G → F → J → L → H → K → E. The lady between F and I is G, so the three ladies are G, H and E - and no two of them are neighbours, as required.

F’s left is the next seat clockwise, which is J’s. G sits on F’s right.

Answer: D

Correct answer: Both are male

J sits between L and F, and G between I and F, so F has J on one side and G on the other, giving the run I – G – F – J – L. H is two seats to J’s left (clockwise), and F sits opposite E, which places the last three. Clockwise the eight seats read I → G → F → J → L → H → K → E. The lady between F and I is G, so the three ladies are G, H and E - and no two of them are neighbours, as required.

The three ladies are G, H and E. J and K are not among them, so both are male - as is F, which the information states outright.

Answer: C

Correct answer: 3

J sits between L and F, and G between I and F, so F has J on one side and G on the other, giving the run I – G – F – J – L. H is two seats to J’s left (clockwise), and F sits opposite E, which places the last three. Clockwise the eight seats read I → G → F → J → L → H → K → E. The lady between F and I is G, so the three ladies are G, H and E - and no two of them are neighbours, as required.

Counting from K to F the short way round gives E, I and G in between; counting the other way gives H, L and J. Either route has three people between them, since they sit directly opposite each other at a table of eight.