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Bose Einstein Statistics Questions and Answers

1.

The formula for energy \(E\) of a photon gas at temperature \(T\) in a two-dimensional box at equilibrium with \(g_{2d}(\nu)\) denoting the density of states of photons is given below where symbols \(\nu\), \(h\) and \(k_{B}\) have their standard meaning. The specific heat (\(C_{V}\)) of this photon gas obeys

\[ \begin{aligned} E = &\int_{0}^{\infty} d\nu\, g_{2d}(\nu) \\ &\times \frac{h\nu}{\exp\left(\frac{h\nu}{k_{B}T}\right) - 1} \end{aligned} \]

Exam Year(s)

GATE Physics - 2026,

Answer: B

The specific heat obeys \(C_{V} \propto T^{2}\).

In two dimensions the number of photon modes with frequency below \(\nu\) grows as the area of a disc in k-space, \(\propto \nu^{2}\), so the density of states is \(g_{2d}(\nu) \propto \nu\). Substituting \(x = h\nu/k_{B}T\):

\[ \begin{aligned} E &\propto \int_{0}^{\infty} \frac{\nu \cdot h\nu}{e^{h\nu/k_{B}T} - 1}\,d\nu \\ &\propto T^{3}\int_{0}^{\infty} \frac{x^{2}}{e^{x} - 1}\,dx \propto T^{3} \\ C_{V} &= \frac{dE}{dT} \propto T^{2} \end{aligned} \]

\(T^{3}\) is the three-dimensional result (from \(E \propto T^{4}\), the Stefan-Boltzmann law), and \(T^{4}\) confuses the 3D energy with its specific heat. \(C_{V} \propto T\) would be the one-dimensional photon gas.

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2.

A system consists of two indistinguishable bosons. Each particle can occupy only two energy levels \( E = \epsilon \) and \( E = 2\epsilon \). The canonical partition function for the system is :

Exam Year(s)

MH SET - 2018, SET Exam - 2018,

Answer: A

The partition function is \( Z = e^{-4\beta\epsilon} + e^{-3\beta\epsilon} + e^{-2\beta\epsilon} \).

For indistinguishable bosons a state is fixed by how many particles are in each level, and any number may share a level. With two particles and two levels there are three states:

  • both in \( \epsilon \): total energy \( 2\epsilon \);
  • one in each level: \( 3\epsilon \), counted once, since the particles cannot be told apart;
  • both in \( 2\epsilon \): \( 4\epsilon \).

Summing \( e^{-\beta E} \) over these three states gives the keyed result. The other options keep a single Boltzmann factor, as if the system had only one state.

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3.

The temperature T of a blackbody enclosure is doubled, then the total number of photons inside the enclosure increases by a factor of :

Exam Year(s)

MH SET - 2023, SET Exam - 2023,

Answer: C

The number of photons increases by a factor of 8.

Integrating the Planck distribution over all frequencies gives the photon number density in a blackbody cavity:

\[ \begin{aligned} n &= \frac{2\zeta(3)}{\pi^{2}}\left(\frac{k_{B}T}{\hbar c}\right)^{3} \\ &\propto T^{3} \end{aligned} \]

Doubling T multiplies n by \(2^{3} = 8\).

The factor 16 is the Stefan-Boltzmann result for the energy density, which goes as \(T^{4}\): the photons become both more numerous and more energetic on average. Factors of 2 and 4 would correspond to linear and quadratic dependences that do not apply to blackbody radiation.

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4.

If the temperature T of photon gas in equilibrium in a radiation cavity is doubled, the equilibrium number of photons will increase by the factor of :

Exam Year(s)

MH SET - 2024, SET Exam - 2024,

Answer: C

The number of photons increases by a factor of 8.

The equilibrium photon number density in a cavity is obtained by integrating the Planck distribution:

\[ \begin{aligned} n &= \frac{2\zeta(3)}{\pi^{2}}\left(\frac{kT}{\hbar c}\right)^{3} \\ &\propto T^{3} \end{aligned} \]

Doubling T multiplies the number by \(2^{3} = 8\). The energy density goes as \(T^{4}\) and would rise 16 times; 2, 6 and 9 do not come from either law.

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5.

The difference between fermions and bosons is that bosons do not obey :

Exam Year(s)

MH SET - 2024, SET Exam - 2024,

Answer: B

Bosons do not obey the Pauli exclusion principle.

Fermions (half-integer spin) have antisymmetric wave functions, so no two can occupy the same quantum state. Bosons (integer spin) have symmetric wave functions and any number can share a state, which leads to Bose-Einstein condensation and laser action.

The Aufbau principle and Hund's rule are rules for filling atomic orbitals with electrons, not a fermion-boson distinction. The uncertainty principle applies to all particles.

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