Direction Sense Test Questions and Answers

Answer: B

Raviraj starts from home at A, moves 20 Km in south upto B. Then he turns right and moves 10 Km upto C, then he turns right and moves 20 Km upto D, then he turns lefts and moves 20 Km upto E.

So from image it is clear that, if he moves straight then he will have to move AD+DE, AD = BC = 10 Km
So, he will have to move 10 + 20 = 30 Km

Answer: A

In the morning sun rises in the East. Hence then any shadow falls in the West. Since Nikharia's shadow was exactly to the right of Nivedita. Hence Nikharia is facing towards North.

Answer: C

Correct answer: 25 km

P and R lie at the ends of two perpendicular arms meeting at Q, so the direct distance is the hypotenuse.

\[d = \sqrt{20^2 + 15^2} = \sqrt{400 + 225} = \sqrt{625} = 25 \text{ km}\]

Answer: A

Starting from his house in the East, Ravi moves westwards. Then, the theatre, which is to the left, will be in the south. The Hospital, which is straight ahead, will be to the West. So, the University will be to the North.

Answer: A

Correct answer: 15 km north

The turns give the sequence east, north, west, north. The 15 km east and 15 km west cancel, while the northward legs add.

\[10 + 5 = 15 \text{ km towards the north}\]

Answer: C

Correct answer: South

In the morning the sun is in the east, so every shadow points west. Stephen’s shadow ran westward and fell to Vimal’s right, so west was on Vimal’s right hand, which puts him facing south.

Answer: C

As shown in fig. the man initially faces in the direction OP. On moving 90º clockwise, he faces in the direction OX. On further moving 180º anticlockwise, he faces in the direction OY. Finally, on moving 90ºanticlockwise, he faces in the direction OZ, which is South-east.

Answer: C

Correct answer: 60 metres

The northward and southward legs cancel - 20 north and then 20 south - leaving \( 40 + 20 = \mathbf{60} \) metres westward.

Answer: A

Correct answer: South-East

Take the relations in the order they are written. \( P \% Q \) fixes P east of Q. \( Q + R \) fixes Q north of R, so R is displaced south from Q. \( R - S \) fixes R west of S, so S is displaced east from R. S is therefore both south and east of Q - south-east. The first relation involving P is not needed for this question and is there to be discarded.

Answer: C

Correct answer: 4 km

Treat the two axes separately.

\[\text{East-west} = 9 - 5 = 4 \text{ km east}, \qquad \text{North-south} = 4 - 4 = 0\]

He ends 4 km due east of where he began.