Profit & Loss Questions and Answers

Answer: D

Let the Cost Price of item \(A\) be \(x\)

Cost Price of item \(B \) is \(x + 200.\)

\(\frac{(\frac{120}{100} \times x)}{(x + 200) \times \frac{70}{100}} = \frac{6}{7} \)

\(\frac{120x}{(x + 200) \times 70} = \frac{6}{7}\)

\(\frac{20x}{10(x + 200)} = 1\)

\(x = Rs 200.\)

Cost Price of item \(B\) is \(200 + 200 = Rs 400.\)

Answer: B

Cost Price (C.P.) \(= Rs. (4700 + 800) = Rs. 5500.\)

Selling Price (S.P.) \(= Rs. 5800.\)

Gain = (S.P.) - (C.P.) \(= Rs. (5800 - 5500) = Rs. 300.\)

Gain % \(= (\frac{300}{5500} \times 100)\)% \(= 5\frac{5}{11}\)%

Answer: C

Let the Cost Price \(= Rs. 100.\) for \(X.\)

\(Y's\) Cost Price \(= Rs. 60.\)

\(Z's\) Cost Price \(= Rs. 84.\)

Finally, \(X's\) Cost Price \(RS. 117.6.\)

\(\therefore X's\) loss \(117.6 - 60 = Rs. 57.6\)

\(\therefore X's \) loss percentage \(= 57.6\)%

Answer: A

Let Cost Price be \(Rs. x.\)

Then, \(\frac{1920 - x}{x} \times 100 = \frac{x - 1280}{x} \times 100\)

\(\Rightarrow 1920 - x = x - 1280\)

\(\Rightarrow 2x = 3200\)

\(\Rightarrow x = 1600\)

\(\therefore \) Required Selling Price \(= 125\) % of \(Rs. 1600 = Rs. (\frac{125}{100} \times 1600) = 2000.\)

Answer: D

(Cost price of \(17 balls\)) - (Selling Price of \(17 balls\)) \(=\) (Cost Price of \(5balls\))

\(\Rightarrow\) Cost Price of \(12 balls\) = Selling Price of \(17 balls \) = \(Rs. 720.\)

\(\Rightarrow\) Cost Price of \(1 balls\)  = \(Rs. (\frac{720}{12}) = Rs. 60.\)

Answer: A

The Cost Price be

\(2120 + 1500 = 3640\)

\(\frac{3640}{2} = 1820.\)

Selling Price \(= \frac{1820 \times 125}{100} = \frac{1820 \times 5}{4}\)

\(= Rs 2275\)

Answer: B

Cost Price of \(56 kg\) rice \(= Rs. (26 \times 20 + 30 \times 36) = Rs. (520 + 1080) = Rs. 1600.\)

Selling Price of \(56kg\) rice \(= Rs. (56 \times 30) = Rs. 1680.\)

\(\therefore\) Gain \(= (\frac{80}{1600} \times 100)\) % \(= 5\) %.

Answer: C

A 15% loss leaves 85% of the cost price.

\[ 1400 \times 0.85 = \text{Rs. } 1190 \]

The loss itself is Rs. 210.

Answer: D

The cost price (CP) of one article \(=1\)

\(\Rightarrow\) CP of \(x\) articles \(=x\) ...........................(Equation 1)

CP of \(20\) articles \(= 20\)

Given that cost price of \(20 \) articles is the same as the selling price of \(x\) articles
\(\Rightarrow\) Selling price (SP) of \(x\)articles \(= \)\(20\)  ............(Equation 2)

Given that Profit \(= 25\)%

Answer: C

Let Cost Price \(= Rs . 100.\)

Then, Profit \(= Rs. 270,\)

Selling Price \(Rs. 370.\)

New Cost Price \(= 130\)% of \(Rs. 100 = Rs. 130\)

New Selling Price \(= Rs. 370.\)

Profit \(= Rs. (370 - 130) = Rs. 240\)

Required  percentage \(= (\frac{240}{370}) \times 100 = 64.86 = 65\)% (approx)