Data Interpretation Questions and Answers

Answer: D

School P had the highest percentage.

In 2017 the selected-to-appeared percentages are: M 94/9200 = 1.02%, N 92/6700 = 1.37%, O 89/6780 = 1.31% and P 93/4500 = 2.07%.

P is the highest. M, N and O are all below 1.4%.

The question asks for the percentage selected out of those who appeared, not the percentage who qualified. P has the smallest number of candidates appearing (4500) and a high number selected (93), which makes its ratio the highest. A common mistake is to pick M, which has the largest number selected, 94.

Answer: B

Copper is the mineral whose production decreased continuously from 1991-92 to 1993-94. Its production was 310, 298 and 288 thousand tonnes in the three years, so it fell in each year.

Lead was 112, 160 and 126, so it rose in 1992-93 and then fell. Nickel was 232, 238 and 248, so it rose every year. Zinc was 98, 108 and 96, so it rose and then fell. A continuous decrease needs a fall at both steps, and only copper has that.

Answer: A

The answer is about 13 per cent. For 2012 add the candidates selected in the five districts: 82 + 70 + 48 + 65 + 55 = 320. Add those who qualified: 640 + 560 + 400 + 525 + 350 = 2475. The required percentage is \[\frac{320}{2475} \times 100 \approx 12.9\] which is about 13 per cent. The options 10, 8 and 15 per cent are further from 12.9. The table was read from the page image, where the 2014 Bankura appeared figure reads 4500.

Answer: B

The difference for school B is 750. From the data the number of students from school B who appeared is 2000 and the number who qualified is 1250. \[ 2000 - 1250 = 750 \] The values 650, 850 and 950 do not match the difference; 650 and 850 are close to it, but they are not the figures of the bars of school B.

Answer: B

A larger area on a radar chart generally indicates higher values across the board. By visual inspection of the data points, Company B has the highest or second-highest values on most metrics (Sales: 90, Profit: 85, Market Share: 75, Customer Sat.: 90). Company A has lower values (e.g., Sales 70, Market Share 60) and Company C also has lower values in some areas (Profit 60, Customer Sat. 70). Therefore, Company B covers the largest area.

Answer: D

Average Company C's four metrics.

\[ 80 + 60 + 80 + 70 = 290 \]

\[ \frac{290}{4} = 72.5 \]

Answer: C

Read the Geography column and average the six marks.

\[ 88 + 92 + 70 + 65 + 85 + 74 = 474 \]

\[ \frac{474}{6} = 79 \]

Answer: B

We need to calculate the total marks for each student.

• Ankit: 90+50+90+88+70 = 388
• Priya: 100+80+80+92+98 = 450
• Rahul: 90+60+70+70+80 = 370
• Suman: 80+65+80+65+75 = 365
• Sneha: 70+75+85+85+65 = 380
• Rohit: 65+55+95+74+70 = 359

Priya has the highest total marks (450).

Answer: C

Suman scored 65 in English and Priya 80.

\[ \frac{65}{80} \times 100 = 81.25\% \]

Priya's mark is the base, since the question asks what Suman's was of hers.

Answer: C

Total marks obtained by Rahul = 90+60+70+70+80 = 370.

The maximum marks for each subject is 100. For 5 subjects, the total maximum marks = 500.

Overall Percentage = \(\frac{\text{Total Marks Obtained}}{\text{Total Maximum Marks}} \times 100\)

= \(\frac{370}{500} \times 100 = 74\)%.