Calendar Questions and Answers

Answer: A

Weekend means Saturday & Sunday together. In total we have 52 weeks in a year. So there are 52 weekends in a year.

In normal we have 104 Weekend Days.

 We know that a Each normal year has 365 days or 52 weeks plus one day, and each week has two weekend days, which means there are approximately 104 weekend days each year.
Whereas in a leap year we have 366 days it adds one more day to the year. And what makes the change is the starting day of the year.

Answer: B

1 December 1991 is a Sunday, so the first Tuesday is the 3rd.

\[ \text{Tuesdays: } 3, 10, 17, 24, 31 \]

The fourth is 24.12.91. The 17th is the third Tuesday, which is why it appears as a distractor.

Answer: B

2nd Jan 1901 means
(1900 years and 2 day)
Now, 1600 years have 0 odd day
300 years have 1 odd day
2 days has 2 odd day
Total no. of odd days = 0 + 1 + 2 = 3 days
Hence, the day on 2nd Jan 1901 was Wednesday.

Answer: C

Let today be \( D \). Yesterday is \( D - 1 \).

Suppose that day were tomorrow instead. If \( D - 1 \) is tomorrow, then "today" in that shifted week is \( D - 2 \), and we are told it would be Friday:

\[ D - 2 = \text{Friday} \quad\Longrightarrow\quad D = \textbf{Sunday} \]

Checking: if today were Sunday, yesterday was Saturday; treating Saturday as tomorrow puts today at Friday, as required.

Answer: B

Only the remainder on division by 7 matters - the odd days.

\[ 61 = 8 \times 7 + 5 \quad\Longrightarrow\quad 5 \text{ odd days} \]

Counting five days on from Monday:

\[ \text{Tue, Wed, Thu, Fri, } \mathbf{Sat} \]

The eight complete weeks return to Monday and contribute nothing.

Answer: D

Count the odd days backwards from 2013 until they total a multiple of seven.

\[ 2012:2,\ 2011:1,\ 2010:1,\ 2009:1,\ 2008:2,\ 2007:1,\ 2006:1,\ 2005:1,\ 2004:2,\ 2003:1,\ 2002:1 \]

\[ \text{total} = 14 \quad\Longrightarrow\quad 0 \text{ odd days} \]

So 2013 repeats the calendar of 2002.

Answer: C

1988 is a leap year, and leap-year calendars repeat every 28 years:

\[ 1988 + 28 = 2016 \]

Both years must be leap years starting on the same weekday for every date to line up, which the 28-year cycle guarantees here.

Answer: A

fifteenth August,2010 =(2009 years+ Period from 1.1.2010 to 15.8.2010)
Odd days in 1600 years = 0.
Odd days in 400 years = 0.

9 year = (2 jump year +7 conventional years)
= (2*2+7*1) = 11 odd days= 4 odd days

Jan + feb + March + April + May + June + July + august
31+28+31+30+31+30+31+15 = 227 days =(32 weeks +3 days )
= 3 odd days

Aggregate no. of odd days = (0+0+4+3) =7
= 0 odd day

Given day is Sunday.

Answer: B

A calendar repeats when the accumulated odd days return to zero. 2024 is a leap year, and leap-year calendars repeat on a 28-year cycle:

\[ 2024 + 28 = 2052 \]

The cycle holds as long as no skipped century year intervenes, and none does between 2024 and 2052.

Answer: D

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)

Odd days in 1600 years = 0

Odd days in 400 years = 0

5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2)  6 odd days

Jan. Feb. March April May (31 + 28 + 31 + 30 + 28 ) = 148 days

 148 days = (21 weeks + 1 day)  1 odd day.

Total number of odd days = (0 + 0 + 6 + 1) = 7  0 odd day.

Given day is Sunday.