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Surds & Indices Questions and Answers

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61.

If \(x = \sqrt{3} + \sqrt{2}\), what is the value of \(\dfrac{1}{x}\) ?

Answer: C

Correct answer: \(\sqrt{3} - \sqrt{2}\)

Rationalise the denominator by multiplying above and below by the conjugate.

\[\frac{1}{\sqrt{3}+\sqrt{2}} \times \frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}-\sqrt{2}} = \frac{\sqrt{3}-\sqrt{2}}{3-2} = \sqrt{3}-\sqrt{2}\]

The denominator becomes \(a^2 - b^2\), which clears both surds at once.

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62.

If \(x\) is an integer, find the minimum value of \(x\) such that \(0.00001154111\times 10^x\) exceeds 1000.

Answer: A

Exp: Considering from the left if the decimal point is shifted by 8 places to the right, the number

becomes 1154.111. Therefore, \(0.00001154111\times 10^x\) exceeds 1000 when \(x\) has a minimum value of 8.

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64.

The simplified form of \((x^{\frac{7}{2}}\div x^{\frac{5}{2}})\times \sqrt{y3}\div \sqrt{y}\) is:

Answer: D

\((x^{\frac{7}{2}}\div x^{\frac{5}{2}})\times \sqrt{y3}\div \sqrt{y} \)

\(= x^{(\frac{7}{2}-\frac{5}{2})}\times y^{(\frac{3}{2}-\frac{1}{2})} \)

\(= xy\)

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65.

\((\frac{1}{216})^{-\frac{2}{3}}\div(\frac{1}{27})^{-\frac{4}{3}}=?\)

Answer: C

\((\frac{1}{216})^{-\frac{2}{3}}\div(\frac{1}{27})^{-\frac{4}{3}} \)

\(= 216^{\frac{2}{3}}\div27^{\frac{4}{3}} \)

\(= (63)^{\frac{2}{3}}\div(33)^{\frac{4}{3}} \)

\(= \frac{4}{9}\)

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66.

\(\frac{1}{1+a^{(n-m)}}+\frac{1}{1+a^{(m-n)}}=?\)

Answer: B

\(\frac{1}{1+a^{(n-m)}}+\frac{1}{1+a^{(m-n)}}=\frac{1}{(1+\frac{a^{n}}{a^{m}})}+\frac{1}{(1+\frac{a^{m}}{a^{n}})}\)

\(=\frac{a^{m}}{(a^{m}+a^{m})}+\frac{a^{m}}{(a^{m}+a^{n})}\)

\(=\frac{(a^{m}+a^{n})}{(a^{m}+a^{n})}\)

=1

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