Machine-translated by Google. Questions are authored in English.
Top

Radiation from a Dipole Questions and Answers

1.

The radiation resistance of a Hertizian dipole antenna of length \(\frac{\lambda}{60}\) is

Exam Year(s)

UGC NET - 2012,

Answer: B

The radiation resistance of a short dipole is \(80\pi^2 (l/\lambda)^2\), which for \(l = \lambda/60\) is about 0.22 ohm (option B).

\[ R_{rad} = 80\pi^2\left(\frac{1}{60}\right)^2 \]

\[ R_{rad} = \frac{789.6}{3600} \approx 0.22\ \Omega \]

The value 0.493 ohm (A) would belong to a longer dipole, near \(\lambda/40\). The values 2.2 and 22 ohm are 10 and 100 times too big, as if the length were \(\lambda/19\) or \(\lambda/6\).

Please log in or register to report this question.

2.

The value of radiation resistance of a Hertizian dipole of length \(\frac{\lambda}{80}\) is given by

Exam Year(s)

UGC NET - 2014,

Answer: D

The radiation resistance is 0.123 ohm. For a short (Hertzian) dipole of length \(l\) the radiation resistance is \(R_{r} = 80\pi^{2}\left(\frac{l}{\lambda}\right)^{2}\). With \(l = \lambda/80\):

\[ R_{r} = 80\pi^{2}\times\frac{1}{6400} \]

\[ R_{r} = \frac{\pi^{2}}{80} \]

\[ R_{r} \approx \frac{9.87}{80} = 0.123\ \Omega \]

The values 0.493, 0.219 and 12.3 ohm do not follow from this formula for \(l/\lambda = 1/80\); 12.3 is just 100 times the correct figure.

Please log in or register to report this question.

Answer: A

Because the field takes time to travel, the potential at a point now depends on the source as it was one propagation time earlier, and writing the source at that retarded time is what turns the static potential integrals into radiating ones. Every radiation result follows from this single modification. Ohmic loss, transient decay and reactive phase lag are all real effects but none of them is what the word retarded refers to here.

Please log in or register to report this question.

Answer: B

The Hertzian or elementary dipole is an idealised element so short that the current may be taken as constant along it, and it serves as the building block from which any wire antenna is assembled by integration. Real short antennas have a current tapering to zero at the ends, which is why their effective length is half the physical length. A half wave dipole, an end fed wire and a crossed pair are all specific practical antennas rather than this abstraction.

Please log in or register to report this question.

Answer: C

The exact solution contains terms in one over r, one over r squared and one over r cubed, and only the first survives to make up the far field. The inverse square term is the induction field and the inverse cube term the electrostatic field, both of which dominate close in and vanish quickly. The distance at which the radiation term overtakes the others is a fraction of a wavelength, which is why the reactive near field is so shallow in wavelengths even for a large antenna.

Please log in or register to report this question.

Answer: D

Only the inverse first power term gives a Poynting vector falling as the inverse square of range, so that the power through a sphere is independent of its radius, which is exactly what radiation means. The other terms carry energy outward and back again within a cycle and transport no net power. That is the cleanest way to distinguish radiation from stored energy, and it explains why the far field is defined by the dominance of a single term, whatever the antenna.

Please log in or register to report this question.

Answer: A

The Poynting vector is the cross product of the electric and magnetic fields and gives the instantaneous power crossing unit area, in watts per square metre. Integrating its time average over a closed surface gives the radiated power, which is how radiation resistance is derived. It points in the direction of propagation, perpendicular to both fields. Energy density and intrinsic impedance are related quantities but are computed differently and mean different things.

Please log in or register to report this question.

8.

The radiation resistance of a short dipole is \( 80\pi^{2}(dl/\lambda)^{2} \). What is it for dl = 0.05 lambda?

Answer: B

Substituting the length ratio directly:

\[ R_{r} = 80\pi^{2}(0.05)^{2} \approx 1.97 \]

giving about 1.97 ohms. Against a conductor and matching loss of even one ohm the efficiency would be barely two thirds, and at a tenth of this length the resistance falls a hundredfold. The square law is the quantitative reason electrically small antennas are inefficient, and it is worth being able to evaluate quickly.

Please log in or register to report this question.

Answer: C

Radiation resistance rises as the square of the length measured in wavelengths, so halving a short antenna quarters its radiation resistance while its loss resistance falls barely at all. That is the whole difficulty of small antennas expressed in one relation. The same square law means that raising the frequency of a fixed physical antenna improves its radiation resistance rapidly, which is why a whip that is hopeless at one frequency can be efficient an octave higher.

Please log in or register to report this question.

Answer: D

The standard thin wire approximation takes a sinusoidal standing wave of current that must vanish at the open ends, since no current can flow into free space there. For a half wave dipole this puts the maximum at the centre, which is why centre feeding gives a convenient impedance. A uniform distribution belongs to the idealised Hertzian element, and the other two shapes describe no physical wire antenna. The assumption is remarkably accurate for thin conductors.

Please log in or register to report this question.

Loading…

Other Subjects

Tags: Radiation from a Dipole Questions and Answers || Radiation from a Dipole MCQ Questions and Answers || Radiation from a Dipole GK Questions and Answers || Radiation from a Dipole GK MCQ Questions || Radiation from a Dipole Multiple Choice Questions and Answers || Radiation from a Dipole GK || GK on Radiation from a Dipole || Antenna and Wave Propagation Questions and Answers || Antenna and Wave Propagation MCQ Questions and Answers || Antenna and Wave Propagation GK Questions and Answers || GK on Antenna and Wave Propagation