Assume that the surface roughness profile is triangular as shown schematically in the figure. If the peak to valley height is 20 μm, the central line average surface roughness Ra (in μm) is

GATE ME - 2017,
Answer: A
The centre line average roughness is 5 μm.
Ra is the mean of the absolute deviations from the centre line. For a symmetric triangular profile of peak-to-valley height h, the centre line lies at h/2 and each deviation varies linearly from 0 to h/2, so its average is h/4:
\[ R_{a} = \frac{h}{4} = \frac{20}{4} = 5\ \mu\text{m} \]
10 μm is the amplitude h/2, the largest deviation rather than the average one, and 20 μm is the full peak-to-valley height. 6.67 μm would be h/3.
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