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Finite Wing Theory Questions and Answers

61.

Wind-tunnel data give a wing of aspect ratio \( 8 \) an induced drag coefficient of \( 0.030 \) at \( C_L = 0.8 \). Its span efficiency factor is nearest to

Answer: A

Rearranging \( C_{D_i} = C_L^2 / (\pi e AR) \) gives \( e = C_L^2 / (\pi AR C_{D_i}) \). Substituting, \( e = 0.64 / (\pi \times 8 \times 0.030) = 0.64 / 0.754 = 0.849 \). A value close to 0.85 is entirely typical of a real wing; a result above one would indicate an error, since the elliptical case is the best a planar wing can do.

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62.

Assertion (A): An elliptical lift distribution gives the least induced drag for a given lift and span.

Reason (R): An elliptical distribution produces a downwash that is uniform across the span.

Select the correct answer from the options below.

Answer: B

Both statements are true and the second explains the first. Minimising the induced drag integral for a fixed lift and span yields the elliptical loading, and the mathematical signature of that optimum is precisely a constant downwash, so no section is working harder against its own induced flow than any other.

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63.

Assertion (A): Induced drag is present even in a completely inviscid calculation.

Reason (R): Induced drag arises from the rearward tilting of the lift vector by the downwash rather than from viscosity.

Select the correct answer from the options below.

Answer: C

Both are true and the reason accounts for the assertion. Induced drag is a pressure drag produced by the geometry of the flow, and the trailing vortex sheet that produces it needs no viscosity to exist in the model. This is why d'Alembert's paradox, which assumes no wake, does not apply to a lifting wing of finite span.

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64.

Assertion (A): A model using one horseshoe vortex of constant strength predicts an unbounded downwash at the wing tips.

Reason (R): The velocity induced by a straight vortex filament varies inversely with the distance from it.

Select the correct answer from the options below.

Answer: D

Both statements are true and the second is the reason for the first. Constant bound strength forces all the shed vorticity into two concentrated tip filaments, and the inverse-distance law then sends the induced velocity to infinity as those filaments are approached. Spreading the shed vorticity along the span removes the singularity.

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65.

Assertion (A): The zero-lift angle of attack of an untwisted finite wing is the same as that of its section.

Reason (R): At zero lift the circulation vanishes at every station, so no vorticity is trailed.

Select the correct answer from the options below.

Answer: A

Both are true and the second explains the first. With no circulation anywhere there is no shed vorticity, hence no downwash and no induced angle, so the wing behaves exactly as its section does. Finite span alters the slope of the lift curve but leaves its intercept on the angle axis untouched.

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66.

Assertion (A): Winglets increase the effective span of a wing.

Reason (R): Winglets add wetted area and therefore increase skin-friction drag.

Select the correct answer from the options below.

Answer: B

Both statements are true, but the second does not explain the first. The effective span increases because the winglet displaces and diffuses the tip vortex, weakening the wing's self-induced downwash. The additional wetted area is a separate and unwanted consequence, which is why winglets pay off only where induced drag is a large share of the total.

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67.

Assertion (A): Sailplanes are built with wings of very high aspect ratio.

Reason (R): The induced drag coefficient of a wing varies inversely with its aspect ratio.

Select the correct answer from the options below.

Answer: C

Both are true and the reason explains the assertion. A sailplane spends its life at high lift coefficient and low speed, where induced drag dominates, so the inverse dependence on aspect ratio is worth a great deal. Aspect ratios above thirty are common, limited chiefly by structural weight and by handling on the ground.

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68.

Assertion (A): Induced drag makes only a small contribution to the total drag of an airliner in cruise.

Reason (R): The induced drag coefficient varies as the square of the lift coefficient.

Select the correct answer from the options below.

Answer: D

Both statements are true and the second accounts for the first. In cruise the aircraft is fast and the required lift coefficient is small, and squaring a small number makes it smaller still. In the take-off climb, where the lift coefficient is several times larger, the same relationship makes induced drag the dominant term.

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69.

Assertion (A): Lifting-line theory gives accurate results for slender delta wings of low aspect ratio.

Reason (R): Lifting-line theory concentrates all the bound vorticity onto a single spanwise line.

Select the correct answer from the options below.

Answer: A

The assertion is false and the reason is true. Concentrating the bound vorticity on one line is a fair approximation only when the chord is small compared with the span and the wing is unswept. A low-aspect-ratio delta violates both conditions, so lifting-surface methods such as the vortex lattice are needed instead.

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70.

Assertion (A): A vortex filament may simply end at an arbitrary point within the fluid.

Reason (R): Helmholtz's theorems require the strength of a vortex filament to be constant along its length.

Select the correct answer from the options below.

Answer: B

The assertion is false and the reason is true, and indeed the reason is what forbids the assertion. A filament must extend to a boundary or close on itself, which is why the bound vortex on a wing has to continue into trailing vortices and close through the starting vortex left behind at the beginning of the motion.

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