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Shear Flow in Open and Closed Sections Questions and Answers

Answer: A

Shear flow is a force per unit length along the wall. It is the natural variable for thin-walled work because it stays constant along a wall of varying thickness, whereas the stress does not, so equilibrium arguments become much simpler.

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Answer: B

A free edge carries no complementary shear, so the flow starts at zero there and accumulates as the first moment of area is swept up. The problem is statically determinate, which is what distinguishes it from the closed-section case.

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Answer: C

Applying the load anywhere else leaves a residual torque equal to the load times its offset from the shear centre, and the section twists as well as bends. Locating the shear centre is therefore essential before any pure-bending analysis can be trusted.

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Answer: D

Symmetry forces the shear flows either side of the axis to mirror one another, so their resultant must lie on it. One axis of symmetry therefore fixes one coordinate of the shear centre and only the other has to be computed.

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Answer: A

Each leg's shear flow produces a force acting along that leg's centreline, so both resultants pass through their intersection and can generate no moment about it. The same argument applies to any section built from legs meeting at a single point, such as a tee.

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6.

For a channel section loaded parallel to the web, the shear centre lies

Answer: B

The flange shear flows form a couple that the web flow alone cannot balance about any point inside the section, so the resultant falls outside it. A load applied at the web will therefore twist a channel, which is why channels are rarely used alone as beams.

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Answer: C

Cutting the section produces an open one that can be solved directly, but the cut has to be restored by a constant redundant shear flow. Finding that redundancy requires a compatibility condition on top of equilibrium, which is what makes the problem indeterminate.

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Answer: D

Equilibrium alone cannot fix the constant, so a deformation condition is added: for a load through the shear centre the twist is zero, and for pure torsion the rate of twist is the same for every cell. That extra equation closes the problem.

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Answer: A

The shear flow is constant round the cell and equals the torque over twice the area enclosed by the wall centreline. Note that it is the enclosed area that matters, not the area of material, which is why closing a section is so much more effective than thickening it.

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Answer: B

Correct answer: Constant, even where the thickness varies

Equilibrium of a small element of wall requires the shear flow \( q = \tau t \) to be the same everywhere round the cell, since any variation would leave an unbalanced axial force. The stress is therefore not constant: it is \( q/t \), and it is largest exactly where the wall is thinnest.

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