In the call calloc(n, size), what do the two arguments represent ?
Answer: A
Correct answer: The number of elements and the size of each element
calloc() multiplies the two arguments to find the total number of bytes, then clears them. Splitting the request in two lets the library detect an overflow in that multiplication, which a single-argument malloc() call cannot do.
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If malloc() successfully allocates memory it returns the number of bytes it has allocated.
Answer: B
Correct answer: FALSE
malloc returns a pointer to the allocated block, not a count of bytes. On success it is the address of the storage; on failure it is null.
The number of bytes is what the caller supplied as the argument, so returning it would convey nothing. There is in fact no portable way to ask how large an allocated block is once it has been made, which is why programs that need to know must record the size themselves alongside the pointer.
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