A box contains 8 white and 3 red balls. If two balls are drawn at random, find the probability that one is white and one is red.
MH SET - 2024, SET Exam - 2024,
Answer: C
The probability is 24/55.
The box holds 11 balls, so two can be drawn in
\[ \binom{11}{2} = \frac{11 \times 10}{2} = 55 \]
ways. One white and one red can be chosen in 8 × 3 = 24 ways, so
\[ P = \frac{8 \times 3}{55} = \frac{24}{55} \]
28/55 is the probability of two white balls (28 ways) and 3/55 that of two red balls (3 ways), so both are answers to different questions.
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