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Network Analysis PERT and CPM Questions and Answers

Direction for [ Question No: 1 To 2 ] :

Statement for Linked Answer Questions:

For a particular project, eight activities are to be carried out. Their relationships with other activities and expected durations are mentioned in the table below.

ActivityPredecessorsDuration (days)
a-3
ba4
ca5
da4
eb2
fd9
gc, e6
hf, g2

1.

The critical path for the project is

Exam Year(s)

GATE ME - 2012,

Answer: C

The critical path is a - d - f - h.

List every path through the network and its duration:

  • a - b - e - g - h: 3 + 4 + 2 + 6 + 2 = 17 days
  • a - c - g - h: 3 + 5 + 6 + 2 = 16 days
  • a - d - f - h: 3 + 4 + 9 + 2 = 18 days

The longest path, 18 days, is the critical path and fixes the project duration.

a - b - e - g - h and a - c - g - h are real paths with slack of 1 and 2 days. a - b - c - f - h is not a path at all: c does not follow b, and f follows d, not c.

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Answer: A

The critical path remains the same and the total duration changes to 19 days.

Activity f lies on the critical path a - d - f - h, so lengthening it by one day lengthens that path to 3 + 4 + 10 + 2 = 19 days. The other paths (17 and 16 days) are unchanged and still shorter, so the critical path is still a - d - f - h.

Any change to a critical activity changes the project duration, so 'total duration remains the same' is wrong. The critical path would change only if another path became the longest, and 17 days is the length of a non-critical path, not the new project duration.

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3.

Which of the following is deterministic model?

Exam Year(s)

DSSSB - 2023,

Answer: B

CPM is a deterministic model, as the key states. In the critical path method the durations of activities are known and fixed, so there is no uncertainty, while PERT uses three time estimates (optimistic, most likely and pessimistic) for each activity, and so it is a probabilistic model. The options that name PERT or both, or neither, are wrong.

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4.

Activities A to K are required to complete a project. The time estimates and the immediate predecessors of these activities are given in the table. If the project is to be completed in the minimum possible time, the latest finish time for the activity G is ____________ hours.

ActivityTime (hours)Immediate predecessors
A2-
B3-
C2-
D4A
E5B
F4B
G3C
H10D, E
I5F
J8G
K3H, I, J

Exam Year(s)

GATE ME - 2022,

Answer: B

The latest finish time for G is 10 hours.

Forward pass (earliest finish): A 2, B 3, C 2; D 6, E 8, F 7, G 5; H starts after D and E, so finishes at 8 + 10 = 18; I 12; J 13; K starts after H, I and J, at 18, and finishes at 21. The project takes 21 hours along the critical path B-E-H-K.

Backward pass: K must finish by 21, so it starts by 18; J must therefore finish by 18 and start by \(18 - 8 = 10\). G is J's only predecessor, so G must finish by 10 hours.

5 is G's earliest finish, 8 confuses it with J's duration, and 9 has no basis. G has 5 hours of slack, so it is not critical.

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