Prashant Arora has three children -- Sangeeta, Vimal and Ashish. Ashish married to Monika, the eldest daughter of Mr. and Mrs. Roy. The Roys married their youngest daughter to the eldest son of Mr. and Mrs. Sharma, and they had two children named Amit and Shashi. The Roys have two more children, Roshan and Vandana, both elder to Veena. Sameer and Ajay are sons of Ashish and Monika. Rashmi is the daughter of Amit.
What is the surname of Sameer ?
Answer: C
Correct answer: Arora
Surnames pass down the male line here. Prashant Arora’s son Ashish is an Arora, and Sameer is a son of Ashish and Monika, so Sameer is an Arora as well. Monika’s own family name, Roy, does not pass to her children.
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How is Mrs. Roy related to Ashish ?
Answer: B
Correct answer: Mother-in-law
Monika is a daughter of Mr and Mrs Roy, and Ashish is married to Monika. Mrs Roy is therefore the mother of Ashish’s wife, which is to say his mother-in-law.
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There are five men A, B, C, D and E and six women P, Q, R, S, T and U, A, B and R advocates;
C, D, P, Q and S are doctors and the rest are teachers. Some terms are to be selected from amongst these eleven persons subject to the following condition :
A, P and U have to be together.
B cannot go with D or R.
E and Q have to be together.
C and T have to be together.
D and P cannot go together.
C cannot go with Q.
If the term is to consist of two male advocates, two lady doctors and one teachers, the members of the team are :
Answer: B
The male advocates are A and B, lady doctors are P, Q and S; teachers are E, T and U.
Now, A and B will be selected.
A, P and U have to be together.
Now, we have to select one lady doctor more. It can be Q or S. But Q and E have to be together. Since E is not selected, so S will be selected.
Thus, the term is A B P U S.
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If the term is to consist of one advocate, two doctors, three teachers and C may not go with T, the members of the team are :
Answer: B
The advocates are A, B and R; doctors are C, D, P, Q, S; teachers are E, T and U.
The term consists of 3 teachers i.e. E, T, U.
Now, A, P, and U have to be together.
E and Q have to be together.
Thus, the team is A E P Q T U.
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If the term is to consists of one male advocate, on male doctor, one lady doctor and two teachers, the members of the term are :
Answer: A
The male advocates are A and B; male doctors are C and D; lady doctors are P, Q and S; teachers are E, T and U.
If A is selectes, P and U will be selected, D and P cannot go together. So, a male doctor C will be selected. C and T have to be together. Thus, the team is A C P T U. If B is selected , D will not be selected. So, male doctor C will be chosen. C and T have to be together. Now, the second teacher to be selecteis E and U. But U cannot go without A. So, wil be selected. E and Q have to be together. Thus, the team can also be B C E Q T.
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If the term is to consists of one advocate, three docotors and one male teacher, the members of the team are :
Answer: C
The advocates are A, B and R; the doctors are C, D, P, Q and S; male teachers is E. Clearly, E will be selected, E and Q have to be together. C and Q cannot be together. So, C will not be selected. P also cannot be selected because U is not selected. So, two other doctors D and S will be selected. P is not selected, so A will not be selected. D is selected, so B cannot be selected. Thus, the team is D E Q R S.
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If the term is to consists of two advocates, two doctors, two teachers and not more than three ladies, the members of the team are :
Answer: A
Correct answer: A B C P T U
Count the categories first: A and B are the two advocates, C and P the two doctors, T and U the two teachers. The ladies are P, T and U, which is three and so within the limit. Every rule holds: A, P and U are together, C and T are together, and B meets neither D nor R. Of the others, two carry four ladies and the last puts B with R.
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A team of five is to be selected from amongst five boys A, B, C, D and E and four girls P, Q, R and S. Some criteria for selecation are :
A and S have to be together.
P cannot be put with R.
D and Q cannot be together.
C and E have to be together.
R cannot be put with B.
Unless otherwise stated, these criteria are applicable to all the question below :
If two of the members have to be boys, the team will consist of
Answer: A
If A is selected, S has to be selected.
If B is selected, R cannnot be selected.
If D is selected, Q cannot be selected.
So, A D S Q R and B D S R Q are wrong. C E S P Q is not possible because S has to be accompanied with A.
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If R be one of the members, the other members of the team are :
Answer: D
Correct answer: S A C E
With R in the team, P is excluded and so is B, since neither may be put with R. Of the four options only one survives the remaining rules: A and S must be together, and C and E must be together, which S A C E satisfies exactly. The others fail - P S A D includes the excluded P, Q S A D puts D with Q, and Q S C E has S without A.
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If two of the members are girls and D is one of the members, the members of the team other than D are :
Answer: C
Correct answer: P S A B
D is in and two members are girls, so the team is three boys and two girls. D bars Q, which eliminates the two options containing her. Of the remaining pair, P S C E puts S in the team without A, breaking the rule that they must be together. P S A B works: A is with S, P is not with R since R is absent, and neither the C-E pair nor the R-B restriction is engaged.
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