Direction Sense Test Questions and Answers

Answer: C

The correct statement is that the chemistry lab is to the southeast of physics lab.

The two roads divide the map into four blocks. The physics lab is in the north-west block (north of 5th Cross Road, west of 1st Main Road) and the chemistry lab is in the south-east block, so the chemistry lab lies to the south-east of the physics lab.

The library is due west of the canteen, both being in the top row, not north-west. The hospital is north of the chemistry lab, on the same side of the main road, not east of it. The classrooms are in the south-west block and the canteen in the north-east block, diagonally opposite, so they are not next to each other.

Answer: C

The trace is the five-pointed star (C).

After the first 72° turn the ant repeats 'forward 10 cm, turn 144° clockwise' five times. Turning by 144° each time means the heading changes by \(5 \times 144 = 720^{\circ}\) in total, two full turns, so the path closes after five equal segments while winding twice around its centre. A closed path of five equal segments that winds twice is a regular star pentagon (pentagram).

A regular pentagon needs turns of 72° (one full turn over five sides), and a hexagon needs six sides with 60° turns. The seven-pointed star has seven segments, but the ant makes only five moves. So only (C) fits.

Answer: A

You end up to the North of the house.

Track the north-south and east-west distances separately.

• North-south: 15 m north, then 5 m south, leaves 10 m north.
• East-west: 10 m west, then 10 m east, cancels out.

So the final position is 10 m due north of the house. South would follow only if the southward leg were longer than 15 m. East and West are ruled out because the two horizontal legs are equal and opposite, so there is no east-west offset at all.

Answer: A

The order is Right, Right, Right.

Facing south, a right turn faces west, a second right turn faces north, and a third right turn faces east. Three right turns are the same as one left turn, and a left turn from south faces east.

The other orders end elsewhere. Left, Left, Left: east, north, west. Left, Right, Right: east, south, west. Right, Left, Right: west, south, west. Only the first sequence finishes facing east.

Answer: A

Sanjay is coming from the North.

In the morning the Sun is in the east, so shadows fall towards the west. Sanjay's shadow falls to his right, so his right hand points west. A person whose right is west is facing south.

Walking while facing south, Sanjay is coming from the north. Shivani walking east does not affect the answer; it only tells us she meets him. If his shadow had been on his left, he would be facing north and coming from the south.

Answer: C

D is facing South.

Partners sit opposite each other at a square table, so A faces C and B faces D. C faces west, so C sits on the east side. Facing west, C's right hand points north, so D, on C's right, sits on the north side of the table.

A player on the north side faces the centre of the table, which is towards the south. B, opposite D, sits on the south side facing north, and A sits on the west facing east.

Answer: B

He is North-East of the starting point.

Track the moves on a grid with East as +x and North as +y: 5 m East takes him to (5, 0), 10 m North to (5, 10), and 5 m East to (10, 10).

His final position is 10 m East and 10 m North of the start, so the direction from the starting point is North-East, at a distance of \(10\sqrt{2} \approx 14.1\) m. The fact that his house faces North is a distractor: it says nothing about the direction of his displacement. North-West and South-East point the wrong way on one axis, and plain North ignores the 10 m he went East.

Answer: B

The bank is 25 km from his house.

Add the East-West and North-South moves separately.

\[ \begin{aligned} \text{East} &= 20 + 15 - 20 - 15 = 0 \\ \text{North} &= -5 - 5 + 35 = 25 \end{aligned} \]

The East-West moves cancel, so he ends 25 km due North of the house, and the straight-line distance is 25 km. 35 km is the last northward leg alone, 40 km comes from adding the North-South legs without signs, and 15 km is one of the westward legs.

Answer: C

The friends are 50 m apart.

Take the start as the origin, East as +x and North as +y.

\[ \begin{aligned} A &= (0, 20) \to (-40, 20) \to (-40, 35) \\ B &= (0, -15) \to (10, -15) \to (10, 35) \end{aligned} \]

Both end at the same height, 35 m North of the start, so the distance between them is the horizontal gap \(10 - (-40) = 50\) m. 35 m is their common northward position, and 60 m comes from adding the East-West distances as if both went the same way.

Answer: A

Only one row is correctly matched.

Each pair of perpendicular moves forms a right triangle, so the distance from O is the hypotenuse.

\[ \begin{aligned} \text{Row 1} &: \sqrt{4^2 + 3^2} = 5 \text{ m, South-East} \\ \text{Row 2} &: \sqrt{8^2 + 15^2} = 17 \text{ m, North-West} \\ \text{Row 3} &: \sqrt{6^2 + 8^2} = 10 \text{ m, South-East} \end{aligned} \]

Row 2 is fully right. Row 1 adds the legs (7 m) instead of using Pythagoras and gives East instead of South-East. Row 3 has the distance right but the direction wrong: 6 m South then 8 m East leaves the person South-East of O, not West.