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True Discount Questions and Answers

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11.

A man wants to sell his scooter. There are two offers, one at Rs. 12,000 cash and the other a credit of Rs. 12,880 to be paid after 8 months, money being at 18% per annum. Which is the better offer?

Answer: A

\[ \text{Amount} = \text{PW}\left(1 + \frac{RT}{100}\right), \qquad \text{TD} = \text{Amount} - \text{PW} \]

Bring the credit offer back to today's money and then compare.

\[ T = \frac{8}{12} = \frac{2}{3} \text{ year}, \qquad \frac{RT}{100} = \frac{18 \times 2/3}{100} = 0.12 \]

\[ \text{PW of credit offer} = \frac{12880}{1.12} = \text{Rs. } 11500 \]

\[ 12000 > 11500 \]

So Rs. 12,000 in cash is worth Rs. 500 more. Eight months of interest at 18% costs more than the extra Rs. 880 the credit offer promises.

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12.

Simran gets a discount of 25% on Rs. 3600 oven. Since she pays cash, she gets additional 2% discount too. How much does she pay?

Answer: D

The cash discount applies to the already-reduced price, so multiply the two factors.

\[ 3600 \times (1 - 0.25) = 3600 \times 0.75 = \text{Rs. } 2700 \]

\[ 2700 \times (1 - 0.02) = 2700 \times 0.98 = \text{Rs. } 2646 \]

Adding the rates to 27% would give Rs. 2628 - Rs. 18 too little, because the 2% is charged on Rs. 2700, not on the full Rs. 3600.

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13.

The true discount on a bill due 9 months hence at 16% per annum is Rs. 189. The amount of the bill is:

Answer: B

The present worth (PW) is what the sum is really worth today; the true discount (TD) is the interest that PW would earn over the remaining time:

\[ \text{Amount} = \text{PW}\left(1 + \frac{RT}{100}\right), \qquad \text{TD} = \text{Amount} - \text{PW} \]

Rearranging gives the standard relation

\[ \text{TD} = \frac{\text{Amount} \times \frac{RT}{100}}{1 + \frac{RT}{100}} \]

Here \( T = \dfrac{9}{12} = 0.75 \) year at 16%:

\[ \frac{RT}{100} = \frac{16 \times 0.75}{100} = 0.12 \]

\[ 189 = \frac{A \times 0.12}{1.12} \quad\Longrightarrow\quad A = \frac{189 \times 1.12}{0.12} = 1764 \]

As a check, PW = 1764 − 189 = 1575, and 12% of 1575 is indeed 189.

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14.

The banker’s gain on a certain sum due 5/2 years hence is 9/25 of the banker’s discount. What is the rate percent?

Answer: D

T = 5/2 year
Let the banker’s discount, BD = Rs.1
Then, banker’s gain, BG = (9/25)*1 = Rs. 9/25
BG = BD-TD
=> 9/25 = 1-TD
=> TD = 1-9/25 = 16/25
F = BD*TD/(BD-TD)
= (1*16/25)/(1-(16/25)) (16/25)/(9/25) = Rs. 16/9
BD = simple interest on the face value of the bill for unexpired time = FTR/100
=> 1 = (16/9)*(5/2)*R/100
=> 100 = (16/9)*(5/2)*R
=> 100 = 16*5*R/9*2
=> 100 = 8*5*R/9
=> R = 100*9/8*5
= 100*9/40 = 5*9/2 = 45/2 = 22 1/2 %

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15.

A man bought a cow for Rs. 3000 in cash and sold it the same day for Rs. 3660, due 2 years hence. If the rate of interest is 10% per annum, the man gains:

Answer: D

\[ \text{Amount} = \text{PW}\left(1 + \frac{RT}{100}\right), \qquad \text{TD} = \text{Amount} - \text{PW} \]

\[ \text{PW} = \frac{3660}{1 + \dfrac{10 \times 2}{100}} = \frac{3660}{1.2} = \text{Rs. } 3050 \]

\[ \text{gain} = 3050 - 3000 = \text{Rs. } 50 \]

\[ \text{gain}\% = \frac{50}{3000} \times 100 = 1.67\% \]

That figure appears nowhere on the list, so the answer is none of these. It is worth contrasting this with the Rs. 3600 version of the same problem, where the present worth comes to exactly Rs. 3000 and the gain is 0%.

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16.

The marked price of a watch is Rs. 800. A shopkeeper gives two successive discounts and sells the watch at Rs. 612. If the first discount is 10%, the second discount is

Answer: C

Work through the first discount, then compare what is left with the selling price.

\[ 800 \times (1 - 0.10) = \text{Rs. } 720 \]

\[ \frac{612}{720} = 0.85 \quad\Longrightarrow\quad \text{second discount} = 15\% \]

Checking: \( 720 \times 0.85 = 612 \).

The combined discount here is \( 1 - 0.90 \times 0.85 = 23.5\% \), which is \( \dfrac{800-612}{800} \) - but the question asks only for the second step.

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17.

A bill falls due in 1 year.The creditor agrees to accept immediate payment of the half and to defer the payment of the other half for 2 years.By this arrangement ins Rs.40.what is the amount of the bill,if he money be worth 12.5%?

Answer: C

Let the bill be \( A \), due in 1 year, with money worth \( 12.5\% \).

Original arrangement - the whole bill in 1 year:

\[ \text{PW}_{\text{old}} = \frac{A}{1 + 0.125} = \frac{A}{1.125} = 0.8889\,A \]

New arrangement - half now (no discount) and half in 2 years:

\[ \text{PW}_{\text{new}} = \frac{A}{2} + \frac{A/2}{1 + 0.25} = 0.5A + 0.4A = 0.9A \]

The creditor gains the difference:

\[ 0.9A - 0.8889A = 0.01111\,A = 40 \]

\[ A = \frac{40}{0.01111} = \text{Rs. } 3600 \]

Deferring half by a further year costs less than being paid the other half a year early gains - because discounting bites harder on the nearer payment.

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18.

If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is:

Answer: A

The present worth (PW) is what the sum is really worth today; the true discount (TD) is the interest that PW would earn over the remaining time:

\[ \text{Amount} = \text{PW}\left(1 + \frac{RT}{100}\right), \qquad \text{TD} = \text{Amount} - \text{PW} \]

True discount is simple interest on the present worth, so start there:

\[ \frac{RT}{100} = \frac{14 \times 2}{100} = 0.28 \]

\[ \text{TD} = \text{PW} \times 0.28 \quad\Longrightarrow\quad 168 = 0.28\,\text{PW} \quad\Longrightarrow\quad \text{PW} = 600 \]

\[ \text{Sum due} = \text{PW} + \text{TD} = 600 + 168 = \text{Rs. } 768 \]

Dividing 168 by 0.28 gives the present worth, not the answer - the discount still has to be added back to reach the sum due.

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19.

The present worth of a certain bill due sometime hence is Rs.800 and true discount is Rs.36. The banker's discount is?

Answer: B

Four quantities are related throughout this topic. Writing \( k = \dfrac{RT}{100} \):

\[ \text{BD} = A\,k, \qquad \text{TD} = \frac{A\,k}{1+k} = \text{PW}\,k, \qquad \text{BG} = \text{BD} - \text{TD} = \text{TD}\,k \]

The banker's discount is interest on the face value; the true discount is interest on the present worth; the banker's gain is the interest on the true discount.

\[ k = \frac{\text{TD}}{\text{PW}} = \frac{36}{800} = 0.045 \]

\[ A = \text{PW} + \text{TD} = 800 + 36 = \text{Rs. } 836 \]

\[ \text{BD} = A\,k = 836 \times 0.045 = \text{Rs. } 37.62 \]

Equivalently \( \text{BD} = \text{TD}(1+k) = 36 \times 1.045 = 37.62 \). The banker's gain is the 62 paise difference.

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20.

The banker's discount on Rs.1600 at 15% per annum is the same as true discount on Rs.1680 for the same time and at the same rate. The time is?

Answer: B

Four quantities are related throughout this topic. Writing \( k = \dfrac{RT}{100} \):

\[ \text{BD} = A\,k, \qquad \text{TD} = \frac{A\,k}{1+k} = \text{PW}\,k, \qquad \text{BG} = \text{BD} - \text{TD} = \text{TD}\,k \]

The banker's discount is interest on the face value; the true discount is interest on the present worth; the banker's gain is the interest on the true discount.

Let \( k \) be the rate–time product. The banker's discount on Rs. 1600 equals the true discount on Rs. 1680:

\[ 1600\,k = \frac{1680\,k}{1+k} \]

Cancelling \( k \):

\[ 1600(1+k) = 1680 \quad\Longrightarrow\quad 1+k = 1.05 \quad\Longrightarrow\quad k = 0.05 \]

\[ \frac{15\,T}{100} = 0.05 \quad\Longrightarrow\quad T = \frac{1}{3} \text{ year} = 4 \text{ months} \]

The rate enters only at the final step; everything before it depends on the ratio \( 1680/1600 \) alone.

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