Problems on Trains Questions and Answers

Q: A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

Trains moving in the same direction close at the difference of their speeds; in opposite directions, at the sum.\[ \text{relative speed} = \frac{108 + 112}{6} = \frac{220}{6} = 36.67 \text{ m/s} \]\[ 36.67 \times \frac{18}{5} = 132 \text{ km/hr} \]\[ v_{2} = 132 - 50 = 82 \text{ km/hr} \]The relative speed is the sum here, so the known 50 km/hr is subtracted from it to leave the second train's speed.

Q: Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:

Trains moving in the same direction close at the difference of their speeds; in opposite directions, at the sum.\[ \text{relative speed} = 60 + 40 = 100 \text{ km/hr} = 100 \times \frac{5}{18} = \frac{250}{9} \text{ m/s} \]\[ t = \frac{140 + 160}{250/9} = \frac{300 \times 9}{250} = 10.8 \text{ seconds} \]

Q: A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?

Each crossing covers the train plus that platform.\[ L + 150 = 15v, \qquad L + 250 = 20v \]\[ 100 = 5v \quad\Longrightarrow\quad v = 20 \text{ m/s} \]\[ L = 15 \times 20 - 150 = 150 \text{ m} \]

Q: Two trains 120 m and 180 m long are running in opposite directions at 54 km/hr and 36 km/hr. How long will they take to cross each other ?

Correct answer: 12 secondsMoving in opposite directions, the speeds add.\[54 + 36 = 90 \text{ km/hr} = 90 \times \frac{5}{18} = 25 \text{ m/s}\]They must together cover the sum of their lengths, 300 m.\[t = \frac{300}{25} = 12 \text{ seconds}\]

Q: A train 200 m long crosses a platform 300 m long in 25 seconds. What is its speed ?

Correct answer: 72 km/hrTo clear a platform the train must cover its own length plus the platform’s.\[\text{Distance} = 200 + 300 = 500 \text{ m}, \qquad \text{Speed} = \frac{500}{25} = 20 \text{ m/s}\]\[20 \times \frac{18}{5} = 72 \text{ km/hr}\]

Q: A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

\[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \]\[ 54 \text{ km/hr} = 15 \text{ m/s} \]The man is a point, so that crossing gives the train's length:\[ L = 15 \times 20 = 300 \text{ m} \]The platform crossing covers train plus platform:\[ 15 \times 36 = 540 \quad\Longrightarrow\quad P = 540 - 300 = 240 \text{ m} \]

Q: A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?

\[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \]\[ 45 \text{ km/hr} = 12.5 \text{ m/s} \]\[ t = \frac{360 + 140}{12.5} = \frac{500}{12.5} = 40 \text{ seconds} \]

Q: A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

The man walks toward the train, so the speeds add.\[ \text{relative speed} = 60 + 6 = 66 \text{ kmph} = 66 \times \frac{5}{18} = \frac{55}{3} \text{ m/s} \]A man is a point, so only the train's own length is covered:\[ t = \frac{110 \times 3}{55} = 6 \text{ seconds} \]Had he walked the same way as the train, the relative speed would be 54 kmph and the answer about 7.3 seconds.

Important Instructions

101.

A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from opposite direction in 6 seconds. The speed of the second train is:

A.48 km/hr
B.54 km/hr
C.66 km/hr
D.82 km/hr

Answer: D

Trains moving in the same direction close at the difference of their speeds; in opposite directions, at the sum.

\[ \text{relative speed} = \frac{108 + 112}{6} = \frac{220}{6} = 36.67 \text{ m/s} \]

\[ 36.67 \times \frac{18}{5} = 132 \text{ km/hr} \]

\[ v_{2} = 132 - 50 = 82 \text{ km/hr} \]

The relative speed is the sum here, so the known 50 km/hr is subtracted from it to leave the second train's speed.

Discuss in Forum

102.

Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:

A.9
B.9.6
C.10
D.10.8

Answer: D

Trains moving in the same direction close at the difference of their speeds; in opposite directions, at the sum.

\[ \text{relative speed} = 60 + 40 = 100 \text{ km/hr} = 100 \times \frac{5}{18} = \frac{250}{9} \text{ m/s} \]

\[ t = \frac{140 + 160}{250/9} = \frac{300 \times 9}{250} = 10.8 \text{ seconds} \]

Discuss in Forum

103.

Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a telegraph post. If the length of each train be 120 metres, in what time (in seconds) will they cross each other travelling in opposite direction?

A.10
B.12
C.15
D.20

Answer: B

A telegraph post is a point, so each crossing gives that train's speed.

\[ v_{1} = \frac{120}{10} = 12 \text{ m/s}, \qquad v_{2} = \frac{120}{15} = 8 \text{ m/s} \]

Running opposite ways they close at the sum and must cover both lengths:

\[ t = \frac{120 + 120}{12 + 8} = \frac{240}{20} = 12 \text{ seconds} \]

Discuss in Forum

104.

A train crosses a platform of 150 m in 15 sec, same train crosses another platform of length 250 m in 20 sec. then find the length of the train?

A.150 m
B.165 m
C.155 m
D.160 m

Answer: A

Each crossing covers the train plus that platform.

\[ L + 150 = 15v, \qquad L + 250 = 20v \]

\[ 100 = 5v \quad\Longrightarrow\quad v = 20 \text{ m/s} \]

\[ L = 15 \times 20 - 150 = 150 \text{ m} \]

Discuss in Forum

105.

Two trains 120 m and 180 m long are running in opposite directions at 54 km/hr and 36 km/hr. How long will they take to cross each other ?

A.10 seconds
B.12 seconds
C.15 seconds
D.18 seconds

Answer: A

Correct answer: 12 seconds

Moving in opposite directions, the speeds add.

\[54 + 36 = 90 \text{ km/hr} = 90 \times \frac{5}{18} = 25 \text{ m/s}\]

They must together cover the sum of their lengths, 300 m.

\[t = \frac{300}{25} = 12 \text{ seconds}\]

Discuss in Forum

106.

A train 200 m long crosses a platform 300 m long in 25 seconds. What is its speed ?

A.60 km/hr
B.66 km/hr
C.72 km/hr
D.80 km/hr

Answer: B

Correct answer: 72 km/hr

To clear a platform the train must cover its own length plus the platform’s.

\[\text{Distance} = 200 + 300 = 500 \text{ m}, \qquad \text{Speed} = \frac{500}{25} = 20 \text{ m/s}\]

\[20 \times \frac{18}{5} = 72 \text{ km/hr}\]

Discuss in Forum

107.

A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

A.120 m
B.240 m
C.300 m
D.None of these

Answer: B

\[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \]

\[ 54 \text{ km/hr} = 15 \text{ m/s} \]

The man is a point, so that crossing gives the train's length:

\[ L = 15 \times 20 = 300 \text{ m} \]

The platform crossing covers train plus platform:

\[ 15 \times 36 = 540 \quad\Longrightarrow\quad P = 540 - 300 = 240 \text{ m} \]

Discuss in Forum

108.

A train is 360 meter long is running at a speed of 45 km/hour. In what time will it pass a bridge of 140 meter length?

A.20 sec
B.30 sec
C.40 sec
D.50 sec

Answer: C

\[ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} \]

\[ 45 \text{ km/hr} = 12.5 \text{ m/s} \]

\[ t = \frac{360 + 140}{12.5} = \frac{500}{12.5} = 40 \text{ seconds} \]

Discuss in Forum

109.

A train 110 metres long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?

A.5 sec
B.6 sec
C.7 sec
D.10 sec

Answer: B

The man walks toward the train, so the speeds add.

\[ \text{relative speed} = 60 + 6 = 66 \text{ kmph} = 66 \times \frac{5}{18} = \frac{55}{3} \text{ m/s} \]

A man is a point, so only the train's own length is covered:

\[ t = \frac{110 \times 3}{55} = 6 \text{ seconds} \]

Had he walked the same way as the train, the relative speed would be 54 kmph and the answer about 7.3 seconds.

Discuss in Forum

110.

A train 400 m long can cross an electric pole in 20 sec and then find the speed of the train?

A.65 Kmph
B.70 Kmph
C.72 Kmph
D.75 Kmph

Answer: C

An electric pole has no length, so the train covers only its own 400 m.

\[ v = \frac{400}{20} = 20 \text{ m/s} \]

\[ 20 \times \frac{18}{5} = 72 \text{ Kmph} \]

Discuss in Forum

Loading…

Topics

Other Subjects

Tags: Problems on Trains Questions and Answers || Problems on Trains MCQ Questions and Answers || Problems on Trains GK Questions and Answers || Problems on Trains GK MCQ Questions || Problems on Trains Multiple Choice Questions and Answers || Problems on Trains GK || GK on Problems on Trains || Quantitative Aptitude Questions and Answers || Quantitative Aptitude MCQ Questions and Answers || Quantitative Aptitude GK Questions and Answers || GK on Quantitative Aptitude

Problems on Trains Questions and Answers

Important Instructions

Topics

Other Subjects

About Us

Stay informed about all important Dates & Notifications