Profit & Loss Questions and Answers

Answer: A

He must sell the remaining land at 25% profit.

Let the whole field cost 1 (one unit). One-third and two-fifths are sold, so the rest is \(1 - \frac{1}{3} - \frac{2}{5} = \frac{4}{15}\). For a 10% overall profit, total sales must be 1.1:

\[ \begin{aligned} \tfrac{1}{3}(0.8) + \tfrac{2}{5}(1.25) &= \tfrac{4}{15} + \tfrac{1}{2} \\ &= \tfrac{23}{30} \\ \text{rest} &= 1.1 - \tfrac{23}{30} = \tfrac{1}{3} \\ \tfrac{1}{3} \div \tfrac{4}{15} &= 1.25 \end{aligned} \]

So the remaining land must fetch 1.25 times its cost, a profit of 25%. The lower options would leave the overall profit below 10%.

Answer: C

Total cost to produced \(1500\) watches \(= (1500 \times 150 + 30000) = Rs. 2,55,000\)

Let he sells \(x\) watches during the season, therefore

Number of watches sold after the season \(= (1500 - x)\)

\(\Rightarrow 250 \times x + (1500 - x) \times 100 = 150x + 150000\)

Now, break - even is achieved if production cost is equal to the selling price.

\(150x + 150000 = 2,55,000\)

\(x = 700\)

Answer: B

Cost Price of \(1st\) transistor \(= Rs. (\frac{100}{120} \times 840) = Rs. 700.\)

Cost Price of \(2nd\) transistor \(= Rs. (\frac{100}{96} \times 960) = Rs. 1000\)

So, total Cost Price \(= Rs. (700 + 1000) = Rs. 1700.\)

Total Selling Price \(= Rs. (840 +960) = Rs. 1800.\)

\(\therefore\) Gain % \(= (\frac{100}{1700} \times 100)\) % \(= 5\frac{15}{17}\) %

Answer: D

Let the Cost Price of item \(A\) be \(x\)

Cost Price of item \(B \) is \(x + 200.\)

\(\frac{(\frac{120}{100} \times x)}{(x + 200) \times \frac{70}{100}} = \frac{6}{7} \)

\(\frac{120x}{(x + 200) \times 70} = \frac{6}{7}\)

\(\frac{20x}{10(x + 200)} = 1\)

\(x = Rs 200.\)

Cost Price of item \(B\) is \(200 + 200 = Rs 400.\)

Answer: B

Cost Price (C.P.) \(= Rs. (4700 + 800) = Rs. 5500.\)

Selling Price (S.P.) \(= Rs. 5800.\)

Gain = (S.P.) - (C.P.) \(= Rs. (5800 - 5500) = Rs. 300.\)

Gain % \(= (\frac{300}{5500} \times 100)\)% \(= 5\frac{5}{11}\)%

Answer: C

Let the Cost Price \(= Rs. 100.\) for \(X.\)

\(Y's\) Cost Price \(= Rs. 60.\)

\(Z's\) Cost Price \(= Rs. 84.\)

Finally, \(X's\) Cost Price \(RS. 117.6.\)

\(\therefore X's\) loss \(117.6 - 60 = Rs. 57.6\)

\(\therefore X's \) loss percentage \(= 57.6\)%

Answer: A

Let Cost Price be \(Rs. x.\)

Then, \(\frac{1920 - x}{x} \times 100 = \frac{x - 1280}{x} \times 100\)

\(\Rightarrow 1920 - x = x - 1280\)

\(\Rightarrow 2x = 3200\)

\(\Rightarrow x = 1600\)

\(\therefore \) Required Selling Price \(= 125\) % of \(Rs. 1600 = Rs. (\frac{125}{100} \times 1600) = 2000.\)

Answer: D

(Cost price of \(17 balls\)) - (Selling Price of \(17 balls\)) \(=\) (Cost Price of \(5balls\))

\(\Rightarrow\) Cost Price of \(12 balls\) = Selling Price of \(17 balls \) = \(Rs. 720.\)

\(\Rightarrow\) Cost Price of \(1 balls\)  = \(Rs. (\frac{720}{12}) = Rs. 60.\)

Answer: A

The Cost Price be

\(2120 + 1500 = 3640\)

\(\frac{3640}{2} = 1820.\)

Selling Price \(= \frac{1820 \times 125}{100} = \frac{1820 \times 5}{4}\)

\(= Rs 2275\)

Answer: B

Cost Price of \(56 kg\) rice \(= Rs. (26 \times 20 + 30 \times 36) = Rs. (520 + 1080) = Rs. 1600.\)

Selling Price of \(56kg\) rice \(= Rs. (56 \times 30) = Rs. 1680.\)

\(\therefore\) Gain \(= (\frac{80}{1600} \times 100)\) % \(= 5\) %.