Given that y = 3 for x = 1 and x varies inversely as the square of y, which of the following options is equal to the value of y, for x = 9?
(y is a positive number.)
DSSSB PGT - 2023,
Answer: A
The value of y is 1. If x varies inversely as the square of y, then \(x y^2\) is constant. From x = 1 and y = 3 the constant is 1 x 9 = 9. For x = 9 we need \[9 y^2 = 9\] so \(y^2 = 1\), and since y is positive, y = 1. The options 9, 2 and 3 give \(xy^2\) values of 729, 36 and 81 at x = 9, which do not equal 9. Check by substitution: with y = 1 the product x times y squared is 9 x 1 = 9, the same as 1 x 3 squared at the start, so the constant holds. The other values of y give 9 x 81 = 729, 9 x 4 = 36 and 9 x 9 = 81, none of which is the constant 9.
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