In an AND gate, the output is HIGH only when all inputs are HIGH.
Answer: A
Correct answer: True
The statement is true. An AND gate outputs 1 only when every one of its inputs is 1; if any input is 0 the output is 0. Its Boolean expression is \( Y = A \cdot B \). Its truth table for two inputs runs: 0,0 gives 0; 0,1 gives 0; 1,0 gives 0; 1,1 gives 1. Only the last row gives 1. A useful way to remember it is that AND behaves exactly like ordinary multiplication on the digits 0 and 1, which is why the operation is written with a dot and often called the logical product. OR is correspondingly called the logical sum, though \( 1 + 1 = 1 \) breaks the analogy there. The AND gate is also used as an enable: holding one input at 1 lets the other pass through unchanged, and holding it at 0 blocks the signal. That is how a clock is gated on and off in practice.
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